Answer:
So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.
Step-by-step explanation:
The height h of the ball is modeled by the following equation
The problem want you to find the times the ball will be 48 feet above the ground.
It is going to be when:
We can simplify by 16t. So
It means that
16t = 0
t = 0
or
t - 2 = 0
t = 2
So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.
Answer:
1i) nth term = 12(-b/4)^(n-1)
ii) nth term = 3(-1/9)^(n-1)
2i) Sixth term= (-3b^5)/256
ii) Eight term = -1/1594323
Question:
The complete question as found on brainly (question-10746111):
Write down the nth term of each of the following G.Ps whose first two terms are given as follows. Also find the term stated besides each G.P.
i) 12,-3b,......sixth term
ii) 3,-1/3,..........;8th term?
Step-by-step explanation:
1) To solve terms involving Geometric progressions (GPs), we would first state the variables that are to be incorporated in the formula.
i) 12,-3b,......;sixth term
1st term = a= 12
r = common ratio = 2nd term /1st term
r = -3b/12 = -b/4
Then we would find the nth term
See attachment for details
ii) 3,-1/3,..........;8th term
1st term = a= 3
r = common ratio = 2nd term /1st term
r = (-⅓)/3 = (-⅓)(⅓) = -1/9
Then we would find the nth term
See attachment for details
2) we are to determine the sixth term in (i) and eight term in (ii)
See attachment for details
Sixth term= (-3b^5)/256
Eight term = -1/1594323
