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scoundrel [369]
3 years ago
6

Could 2.8 cm, 4.0 cm and 2.8 cm be the side lengths of a triangle?

Mathematics
1 answer:
elixir [45]3 years ago
7 0

Answer:

Yes they can

Step-by-step explanation:

Please mark brainlest and thank me... Have a blessed day

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Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k
ch4aika [34]

Given

\vec v =  f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k

the curl of \vec v is

\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k

\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k

\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k

7 0
3 years ago
I have four times as much money as my brother has. Our total is $55. How much does each of us have?
padilas [110]

Answer:

27.5

Step-by-step explanation:

6 0
3 years ago
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1. De un tubo vertical cuyo radio interior es 1 mm gotea agua. Hallar el radio de las gotas en el momento de desprenderse. Hay q
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Step-by-step explanation:

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3 years ago
What fraction of 42 g is 7000 mg​
Vsevolod [243]

Answer:

3/500

Step-by-step explanation:

42/7000 simplified is 3/500 or in decimal form it's 0.006

4 0
3 years ago
Is what i did correct?
yaroslaw [1]
No, you should have reduced each base to...
3^(3*2x) = 3^(2*(x-3))
and then you can cancel each base
3*2x = 2*(x-3)
6x = 2x-6
4x= -6
x = -3/2
7 0
3 years ago
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