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alexdok [17]
3 years ago
12

Describe a situación that could be modeled whit the ratio 4:1.

Mathematics
1 answer:
Arada [10]3 years ago
3 0
Your mom was outnumber 4 D to one V
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Choose all the numbers that are common multiples of 3 and 12
Andre45 [30]

Answer:

Step-by-step explanation:

-48

-72

-84

basically if its divisible by 12 its divisible by 3

6 0
3 years ago
Figure ABCD is transformed to obtain figure A′B′C′D′:
xz_007 [3.2K]

Answer:

<u>Part A</u>

  1. Reflect over the y-axis:  (x, y) → (-x, y)
    A (-4, 4) → (4, 4)
    B (-2, 2) → (2, 2)
    C (-2, -1) → (2, -1)
    D (-4, 1) → (4, 1)
  2. Shift 4 units down:  (x, y-4)
    (4, 4-4) → A' (4, 0)
    (2, 2-4) → B' (2, -2)
    (2, -1-4) → C' (2, -5)
    (4, 1-4) → D' (4, -3)

<u>Part B</u>

Two figures are <u>congruent</u> if they have the same shape and size.  (They are allowed to be rotated, reflected and translated, but not resized).

Therefore, ABCD and A'B'C'D' are congruent.  They are the same shape and size as they have only be reflected and translated.

3 0
2 years ago
How long will it take for an investment of $2000 to double in value if the interest rate is 7.25%
lesya692 [45]

Answer:

t = ln2/0.075

t = 9.24 years.

hope this helps

3 0
3 years ago
Show your working please.​
iren2701 [21]

Offer B is the best value for money because each kg cost is £0.61 and in offer 'A' each kg cost is £0.7.

<h3>What is a fraction?</h3>

Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

We have:
2 bags for £35

2 bags means 50 kg (2×25)

Each kg cost = 35/50 = £0.7 per kg

3 bags for £92.50

3 bags means 150 kg

Each kg cost = 92.50/150 = £0.61 per kg

As we can see, offer B has a low cost per kg

Thus, offer B is the best value for money because each kg cost is £0.61 and in offer 'A' each kg cost is £0.7.

Learn more about the fraction here:

brainly.com/question/1301963

#SPJ1

6 0
2 years ago
Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function.
marishachu [46]

Answer:

\text{Possible rational zeros}=\pm1,\pm\frac{1}{2},\pm2,\pm3,\pm\frac{3}{2},\pm6,\pm9,\pm\frac{9}{2},\pm18

Step-by-step explanation:

We have been given the function

f(x)=-2x^2+4x^3+3x^2+18

From the rational zeros theorem, we have

\text{Possible rational zeros}=\pm\frac{\text{Factors of constant term}}{\text{Factors of leading coefficient}}

From the given function,

Leading coefficient = 2

Factors of 2 are 1,2

Constant term = 18

Factors of constant term = 1, 2, 3, 6, 9, 18

Hence, we have

\text{Possible rational zeros}=\pm\frac{1,2,3,6,9,18}{1,2}\\\\\text{Possible rational zeros}=\pm1,\pm\frac{1}{2},\pm2,\pm3,\pm\frac{3}{2},\pm6,\pm9,\pm\frac{9}{2},\pm18

6 0
3 years ago
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