Answer:
Interval of 50 on both axis
Step-by-step explanation:
Given
There are several ways to do this, but I will use the observation method, since the dataset is small.
Considering the x-coordinates
Each element of the data set is a multiple of 50.
Hence, an interval of 50 can be used on the x-axis
Considering the y-coordinates
Each element of the data set is a multiple of 50.
Hence, an interval of 50 can be used on the y-axis
<em>So, an interval of 50 can be used on both axes</em>
Answer:
is there more to the question?
4/5*9/10= 36/50 = 18/25
Just multiply the fractions straight across since area is length*height
This is how the sketch should look on your graph!
Answer: x = -0.2651 and y = -0.9759
Step-by-step explanation:
Solution by substitution method
8x+5y= -7
-7x+6y= -4 = 7x-6y=4
Suppose,
8x+5y=-7→(1)
7x-6y=4→(2)
Taking equation (1), we have
8x+5y= -7
⇒8x= -5y -7
⇒x= -5y-7 / 8 →(3)
Putting x= -5y-7 / 8
in equation (2), we get 7x-6y=4
7(-5y-7/8)-6y=4
⇒-35y-49-48y=32
⇒-83y-49=32
⇒-83y=32+49
⇒-83y=81
⇒y= 81 / -83
⇒y= -0.9759→(4)
Now, Putting y= -0.9759 in equation (3), we get
x= -5y-7
x= -5(-0.9759)-7/8
⇒x= 4.8795-7/8
⇒x= -2.1205/8
⇒x= -0.2651
∴x= -0.2651 and y = -0.9759
