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Klio2033 [76]
3 years ago
9

Is 4.39463 a natural number

Mathematics
2 answers:
zubka84 [21]3 years ago
7 0

Answer:

I think it is natural number. hope it helps

Step-by-step explanation:

Bezzdna [24]3 years ago
3 0

Answer:

i wanna say yes it is a natural number, i hope this helps

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According to the law of reflection, if the angle of incidence of an incoming ray
Natalija [7]

Answer:

The answer is the option B, which is: 46 degrees.  

The explanation for this problem is shown below:

1. According to the Law of reflection, the angle of incidence is equal to the angle of reflection.

2. Therefore, if Ф1 is the angle of incidence and Ф2 is the angle of reflection, you have:

Ф1 = 46 degrees

Ф1 = Ф2

Ф2 = 46 degrees

So, the answer is the option mentioned before.

4 0
3 years ago
Read 2 more answers
The hypotenuese of an isosceles right triangle is 16 inches. The midpoints of its sides are connected to form an inscribed trian
ser-zykov [4K]

Answer:

  256/3 = 85 1/3 square inches

Step-by-step explanation:

The dimensions of the first inscribed triangle are 1/2 those of the original, so its area is (1/2)² = 1/4 of the original. The area of the original is ...

  A = (1/2)bh = (1/2)(16/√2)(16/√2) = 64 . . . . square inches

The sum of an infinite series with first term 64 and common ratio 1/4 is ...

  S = a1/(1 -r) . . . . . . for first term a1 and common ratio r

  = 64/(1 -1/4) = 64(4/3) = 256/3 . . . . square inches

The sum of the areas of the triangles is 256/3 = 85 1/3 square inches.

3 0
3 years ago
…………………………………………………………………………………………………………………….…………………
ale4655 [162]
We can split this up into 3 rectangles.  2 vertical ones (8 x 3) and one horizontal one in the middle (5 x (8 - 5)

8 x 3 = 24
24 x 2 = 48

5 x (8-5) = 5 x 3 = 15

now add 48 + 15 = 63 cm^2
6 0
3 years ago
Good morning yall <3 say it back free points !!
NeTakaya

Answer:

okay thanks didn't expect this lol

6 0
3 years ago
Read 2 more answers
Consider the following differential equation. x^2y' + xy = 3 (a) Show that every member of the family of functions y = (3ln(x) +
Veronika [31]

Answer:

Verified

y(x) = \frac{3Ln(x) + 3}{x}

y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{x}

Step-by-step explanation:

Question:-

- We are given the following non-homogeneous ODE as follows:

                           x^2y' +xy = 3

- A general solution to the above ODE is also given as:

                          y = \frac{3Ln(x) + C  }{x}

- We are to prove that every member of the family of curves defined by the above given function ( y ) is indeed a solution to the given ODE.

Solution:-

- To determine the validity of the solution we will first compute the first derivative of the given function ( y ) as follows. Apply the quotient rule.

                          y' = \frac{\frac{d}{dx}( 3Ln(x) + C ) . x - ( 3Ln(x) + C ) . \frac{d}{dx} (x)  }{x^2} \\\\y' = \frac{\frac{3}{x}.x - ( 3Ln(x) + C ).(1)}{x^2} \\\\y' = - \frac{3Ln(x) + C - 3}{x^2}

- Now we will plug in the evaluated first derivative ( y' ) and function ( y ) into the given ODE and prove that right hand side is equal to the left hand side of the equality as follows:

                          -\frac{3Ln(x) + C - 3}{x^2}.x^2 + \frac{3Ln(x) + C}{x}.x = 3\\\\-3Ln(x) - C + 3 + 3Ln(x) + C= 3\\\\3 = 3

- The equality holds true for all values of " C "; hence, the function ( y ) is the general solution to the given ODE.

- To determine the complete solution subjected to the initial conditions y (1) = 3. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y( 1 ) = \frac{3Ln(1) + C }{1} = 3\\\\0 + C = 3, C = 3

- Therefore, the complete solution to the given ODE can be expressed as:

                        y ( x ) = \frac{3Ln(x) + 3 }{x}

- To determine the complete solution subjected to the initial conditions y (3) = 1. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y(3) = \frac{3Ln(3) + C}{3} = 1\\\\y(3) = 3Ln(3) + C = 3\\\\C = 3 - 3Ln(3)

- Therefore, the complete solution to the given ODE can be expressed as:

                        y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{y}

                           

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6 0
3 years ago
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