Answer:
Step-by-step explanation:
Let 
represent the length of the rectangle. The width can be represented as 
.
The perimeter of a rectangle with lengths 
and 
is given by 
.
Thus, we have:
The width is then 
.
Check the picture below.
so... you can pretty much see how long RS and QT are, you can just count the units off the grid.
now, let's find QR's length
and let's also find the length for ST
so, add the lengths of all sides, and that's the perimeter of the trapezoid.
Answer:
Volume = ⅓n²(n-1) or ⅓(n³ - n²)
Step-by-step explanation:
Given
Solid Shape: Right pyramid
Edge= n units
Height= n - 1 units
Required
Volume of the pyramid
The volume of a right pyramid is
Volume = ⅓Ah
Where A represents the area of the base
h represent the height of the pyramid
Since it has a square base;
The area is calculated as follows
Area, A = edge * edge
A = n * n
A = n²
Recall that
Volume = ⅓Ah
Substitute n² for A and n - 1 for h
The expression becomes
Volume = ⅓ * n² * (n - 1)
Volume = ⅓n²(n-1)
The expression can be solved further by opening the bracket
Volume = ⅓(n³ - n²)
Answer:
The coordinates are (2,8)
Step-by-step explanation:
A hole is where both the numerator and the denominator are zero
f(x)=x^2+4x−12 / x−2
Factor the numerator
f(x) = (x+6) (x-2)/ (x-2)
The hole will occur where x-2 =0
x-2=0
Add 2 to each side
x-2+2 =0+2
x=2
There is a hole at x=2
If we could cancel the x-2 values from the top and bottom, we are left with
f(x) = x+6
At x=2
f(2) = 6+2
f(2) would be 8
The coordinates are (2,8)
There is a hole
Answer: 45°
Step-by-step explanation: add the angles together to get a total of 180°
