For 6 I think it was B I am not so sure. Its been a long time since i did triangles
Start with an equation summing all the angles in this triangle:
180 = <M + <N + <P
we are given <M and <N but not <P. But, since MN=NP, the angle <P is the same as the angle <M (isosceles, make a drawing to see). So
180 = 2<M + <N
180 = 2(3x+1) + x-11
180 = 7x - 9
x = 27
<P = 3*27+1 = 82 degrees
Answer:
The answer is 6z-28
Step-by-step explanation:
20 - 3[4(z+1) - 6(z-2)]
= 20 - 3(4z+4-6z+12)
= 20 - 3(16 - 2z)
= 20 - 48 + 6z
= 6z - 28
Line b is the answer, hope this helped
4. SOLVE FOR X:
Using the Alternate Interior Angles Theorem, we know that the 67 degree angle is congruent with the (12x - 5) degree angle. With this information, all I have to do is set the two equal to each other and solve for x.
67 = 12x - 5
67 + 5 = 12x - 5 + 5
72/12 = 12x/12
6 = x
x = 6
SOLVE FOR Y:
Using the Vertical Angles theorem, we know that angle y must be congruent to the 67 degree angle.
y = 67 degrees.
5. SOLVE FOR Y:
Alternate exterior angles: 6(x - 12) = 120
6x - 72 + 72 = 120 + 72
6x/6 = 192/6
x = 32
SOLVE FOR Y:
6((32) - 12) + y = 180
192 - 72 + y = 180
120 + y - 120 = 180 - 120
y = 60
