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erastovalidia [21]
3 years ago
12

A ball, thrown vertically upwards, from the ground, has its height h (in meters) expressed as a function of time t (in seconds),

elapsed after the launch, by the law h(t) = 20t - 5t2. According to this information, determine the height at which the ball is 3 seconds after the throw and the maximum height reached by the ball.
Mathematics
1 answer:
zhuklara [117]3 years ago
5 0
Height at 3 sec: 15 meters

Max height: 20 meters
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Please help me with this
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8 0
2 years ago
There are five cars in line at a stoplight. Each of these cars is a different color and different type of car. Diego is driving
adell [148]
Ok, here we go:
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8 0
3 years ago
A number is first increased by 20 and then doubled. The result is 2 less than 5 times
Iteru [2.4K]

i  think maybe ? x+20*2=5-2*x

8 0
2 years ago
(2×-5) for ×=-3 and for ×=3.​
Brut [27]

Answer:

<h2>-11 and 1</h2>

Step-by-step explanation:

Put the values of x to the given expression:

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for x = 3

2(3) - 5 = 6 - 5 = 1

6 0
3 years ago
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