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9966 [12]
4 years ago
11

A real flowing fluid A. does not experience turbulence B. has a constant density C. has a constant velocity at a given location

in the flow D. exhibits viscosity
Physics
1 answer:
coldgirl [10]4 years ago
6 0
D. exhibits viscosity
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A steel piano string of mass per unit lenght 4×10-⁴kgm-¹ was struck, if the speed of the sound on the string is 300ms-¹. Calcula
Snezhnost [94]

Answer:

36 N

Explanation:

Velocity of a standing wave in a stretched string is:

v = √(T/ρ),

where T is the tension and ρ is the mass per unit length.

300 m/s = √(T / 4×10⁻⁴ kg/m)

T = 36 N

7 0
3 years ago
1-D catch-up: Two cars move with constant velocities. At t = 0, a blue car is at xBo = 20 m. After t = 4s in the blue car time f
OlgaM077 [116]

Answer:

5.71 m/s ;

20 m/s

Explanation:

Blue car:

At time, t = 0 ; Initial position = 20 m

Final position, = 60m after 4 seconds

The velocity = change in distance / change in time.

Velocity of blue = (60 - 20)m ÷ ((4 + 3) - 0),

Velocity of blue car = 40 / 7

= 5.71 m/s

Red car:

Initial Position = 0 ; final Position = 60

Time taken = 3 seconds

Velocity of Red car = (60 - 0)m ÷ 3

Velocity of Red car = 60 / 3

= 20 m/s

6 0
3 years ago
14. The United States Tobacco Settlement between the major tobacco companies and 46 states caused the price of cigarettes to jum
AysviL [449]

Answer:

B. The elasticity of demand is -0.126

Explanation:

% Change in Quality demand = -2.65% (negative because of drop)

% Change in price = 21%

Elasticity of demand is given by

\text{Elasticity of demand}=\dfrac{\text{\% Change in Quality demand}}{\text{\% Change in price}}\\\Rightarrow \text{Elasticity of demand}=\dfrac{-2.65}{21}\\\Rightarrow \text{Elasticity of demand}=-0.12619

The Elasticity of demand is -0.12619

8 0
4 years ago
The weld current between pulses is know as ______
Brut [27]

Answer:

the pulse arc system  

Explanation:

6 0
3 years ago
What is the radiation pressure 1.5 m away from a 700 W lightbulb? Assume that the surface on which the pressure is exerted faces
baherus [9]

Answer:

3.30 x 10^-7 Pascal

Explanation:

distance r = 1.5 m

power P = 700 W

the radiation pressure is given as

Pr = P/A*c

where

area of the surface A = 4πr^2

calculate for A

speed of light is c = 3×10^8  m/s

plugging above values in equation above gives

Pr = 3.30 x 10^-7 Pascal

3 0
3 years ago
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