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asambeis [7]
4 years ago
14

A piece of stone is thrown up from a height of 25 meters above the ground. after 2 seconds the stone reaches the highest point.

Physics
1 answer:
Natasha2012 [34]4 years ago
3 0

Answer:

A. 19.6 m/s

B. 44.6 m

C. 5.0 s

D. -19.6 m/s

Explanation:

At the highest point, the stone's velocity is 0.

A. Given:

v = 0 m/s

t = 2 s

a = -9.8 m/s²

Find: v₀

v = at + v₀

0 = (-9.8)(2) + v₀

v₀ = 19.6 m/s

B. Given:

y₀ = 25 m

t = 2 s

v₀ = 19.6 m/s

a = -9.8 m/s²

Find: y

y = y₀ + v₀ t + ½ at²

y = 25 + (19.6)(2) + ½(-9.8)(2)²

y = 44.6 m

C. Given:

y₀ = 25 m

y = 0 m

v₀ = 19.6 m/s

a = -9.8 m/s²

Find: t

y = y₀ + v₀ t + ½ at²

0 = 25 + (19.6)t + ½(-9.8)t²

0 = 4.9t² − 19.6t − 25

t ≈ 5.0 s

D. Given:

v₀ = 19.6 m/s

a = -9.8 m/s²

t = 4 s

Find: v

v = at + v₀

v = (-9.8)(4) + 19.6

v = -19.6 m/s

The velocity is -19.6 m/s.  If you want the speed, or magnitude of the velocity, take the absolute value: 19.6 m/s.

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A man goes 150 m due east and then 200 m due north how far is he from starting point
grin007 [14]

Answer:

250 m

Explanation:

Since North and East are 90 degrees from each other, we can treat this as a right-angled triangle, with the distance in each direction being the sides and the distance from the starting point being the hypotenuse.

Hence, sqrt(150^2+200^2) = 250 m.

Hope this helped!

7 0
3 years ago
hi, Need help with triangle law of vector addition worksheet and a verifying Newtons second law worksheet?
Yuri [45]

Use Newton's second law and the free body diagram to determine the net force and acceleration of an object. In this unit, the forces acting on the object were always directed in one dimension.

The object may have been subjected to both horizontal and vertical forces but there was no single force directed both horizontally and vertically. Moreover, when free-body diagram analysis was performed, the net force was either horizontal or vertical, never both horizontal and vertical.

Times have changed and we are ready for situations involving two-dimensional forces. In this unit, we explore the effects of forces acting at an angle to the horizontal. This makes the force act in two dimensions, horizontal and vertical. In such situations, as always in situations involving one-dimensional network forces, Newton's second law applies.

Learn more about Newton's second law here:-brainly.com/question/25545050

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5 0
1 year ago
Collapse question part Part 4 (d) What is the unit vector in the direction of the spacecraft's velocity? (Express your answer in
Maksim231197 [3]

Answer:

unit (v) = [ -0.199 i - 0.8955 j + 0.39801 k ]

Explanation:

Given:

                            v =  (-23.2, -104.4, 46.4) m/s

Above expression describes spacecraft's velocity vector v.

Find:

Find unit vector in the direction of spacecraft velocity v.

Solution:

Step 1: Compute magnitude of velocity vector.

                            mag (v) = sqrt ( 23.2^2 + 104.4^2 + 46.4^2)

                            mag (v) = 116.58 m/s

Step 2: Compute unit vector unit (v)

                            unit (v) = vec (v) / mag (v)

                            unit (v) = [ -23.2 i -104.4 j + 46.4 k ] / 116.58

                            unit (v) = [ -0.199 i - 0.8955 j + 0.39801 k ]

7 0
3 years ago
If you wanted to
VLD [36.1K]

Answer:

Option C

Explanation:

According to the formula

  • \\ \boxed{\sf R=\rho\dfrac{\ell}{A}}

So

If we use wide wire we increase the area of cross section so resistance decreases

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2 years ago
What are the scientific mesurments ordered from greatest to least
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