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Natali [406]
2 years ago
12

Un hamster esta sentado sobre un tocadisco cuya rapidez angular es constante si el hamster se mueve a un punto localizado al dob

le de la distancia del centro entonces su rapidez lineal...
a) sera la mitad
b) se duplica
c) se mantendra igual
Physics
1 answer:
kotegsom [21]2 years ago
8 0

Answer:

b) se duplica

Explanation:

The disk is moving with constant angular velocity, let's call it \omega.

The linear velocity of a point on the disk is given by

v=\omega r

where r is the distance of the point from the axis of rotation.

In this problem, the object is moved at a distance twice as far as the initial point, so

r' = 2r

Therefore, the new linear velocity is

v'=\omega r' = \omega (2r) = 2 \omega r = 2 v

So, the velocity has doubled, and the correct answer is

b) se duplica

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What two factors determine the amount of friction there will be between objects?
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the two factors are the mass of the objects and the coefficient of friction between them

Explanation:

internet :)

6 0
3 years ago
the video identifies the force pair produced when an apple falls through the air. which force belongs in a free-body diagram of
trapecia [35]

The free-body diagram of an apple falling through the air has weight of the apple pointing downwards and the air-resistance on the apple acting upwards.

When an object falls from up to the ground, the object falls under in the influence of acceleration due to gravity.

The vertical component of the force on the apple as it falls trough the air is given as;

∑Fy = 0

Fₙ - W = 0

Fₙ = W

where;

  • <em>Fₙ is the frictional force on the apple acting upwards</em>
  • <em>W is the weight of the apple acting downwards</em>

The free-body diagram of the apple is represented as follows;

                                         ↑ Fₙ

                                         Ο

                                         ↓ W

Thus, the free-body diagram of an apple falling through the air has weight of the apple pointing downwards and the air-resistance on the apple acting upwards.

Learn more here:brainly.com/question/18770265

6 0
2 years ago
A car is traveling north at 17.7 m/s . After 6 it’s velocity is 141 in the same direction. Find the magnitude and direction of t
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By equation of motion we have   v = u + at

Where u = Initial velocity, v = final velocity, t = time taken and a = acceleration

Here v = 141 m/s, u = 17.7 m/s and t = 6 s

On substitution we will get

        141 = 17.7+ 6a

       So, a = (141-17.7)/6 = 20. 55 m/s^{2}

       Aceeleration = 20. 55 m/s^{2} along north direction.


3 0
3 years ago
A car is traveling 16 m/s East. If the car then speeds up at a constant acceleration, what is the direction of the car’s acceler
konstantin123 [22]
The direction is east since its constant
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kykrilka [37]
It’s A.Longitudinal. Tell me if I’m right
4 0
2 years ago
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