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2 years ago

1 over 2z = 3 over 4. Which of the following equals z in this equation? 3 over 8 2 over 3 1 over 1 over 2 2 over 2 over 3

Mathematics

2 answers:

Yanka [14]2 years ago

5 0

The answer is

C. 1 1/2

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Hope This Helps!

katovenus [111]2 years ago

5 0

Answer:

The answer is

C. 1 1/2

Step-by-step explanation:

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Z=y/xm , solve for x

fgiga [73]

Answer:

y/mz

Step-by-step explanation:

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3 years ago

What is the sum of the given polynomials in standard form ? (X^2-3x)+(-2x^2+5x-3)

Greeley [361]

$(x^2-3x)+(-2x^2+5x-3)=x^2-3x-2x^2+5x-3\\\\=(x^2-2x^2)+(-3x+5x)-3=-x^2+2x-3$

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3 years ago

4t2–40t+84 factorise quadratics

Evgen [1.6K]

Answer:

4( t - 7) ( t - 3 )

Step-by-step explanation:

4t² - 40t + 84

4(t² - 10t + 21)

4( t - 7) ( t - 3 )

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2 years ago

Read 2 more answers

Which expression is equivalent to (x^4/3 x^2/3)^1/3?

KATRIN_1 [288]

Answer: $x^{\frac{2}{3} }$

Step-by-step explanation:

We have several properties of exponents in use here. The two that are used are:

$(x^{a})(x^{b}) = x^{a + b}$ (Exponents with the same base that are being multiplied together can have the exponents added)

$(x^{a})^{b} = x^{(a)(b)}$ (A base raised to a power, and then raised to another power means that you can multiply the exponents to get the same result as doing inside operations and then outside operations)

Let's apply it!

First, let's simplify what's inside the parenthesis.

$x^{\frac{4}{3} } x^{\frac{2}{3} }$ (Remember, they have the same base of "x", so we can add the exponents)

$x^{\frac{4}{3} + \frac{2}{3} }$ = $x^{\frac{6}{3} }$ = $x^{2}$

Now we have $(x^{2})^{\frac{1}{3} }$ . Let's use the second rule.

$(x^{2})^{\frac{1}{3} }$ = $x^{\frac{2}{3} }$

Hope this helps! :^)

7 0

3 years ago

2 over 5 blank over 10 which is 0.4 in decimal form.

Tomtit [17]

2/5 = ?/10 = 0.4
2*(2/5) = (2*2)/(2*5) = 4/10
? = 4

8 0

3 years ago