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1 answer:
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Remark.
The problem is a bit indistinct. Where exactly are the two edges of the road? I'm going to say that they are the x intercepts, but that may not be true. Certainly it does not have to be true at all.
Graph.
A graph has been made for you. The maximum is marked for you. It is an approximation The actual height can be more accurately found.
Height
y = (-1/200)(x - 16)(x + 16)
y = (-1/200)*(x^2 - 256)
The maximum height for this graph only is when x = 0.Other graphs require completing the square.
y = (-1/200) * (-256)
y = 1.28 exactly. I thought the graph might be rounding the answer. It is not.
Answer:
Step-by-step explanation:
Sin theta is the ratio of side opposite over hypotenuse of a reference angle situated at the origin in an x-y coordinate plane. If sec theta is negative, then the only quadrant where sin is positive AND sec is negative is quadrant 2. Remember that sec theta is the inverse of cos theta. Puttling our right triangle in QII, the side measuring 7 is across from the angle and the hypotenuse is 11. In order to find the cos theta and tan theta, we need the side adjacent to the angle. Use Pythagorean's Theorem to find the side adjacent.
and
and
so
Remember that this value is why the sec is negative. Because x is negative in QII, the cos theta is side adjacent over hypotenuse:
and
But we should probably rationalize that denominator, so