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3 years ago

URGENT:

Mathematics

1 answer:

AfilCa [17]3 years ago

8 0

Answer:

Question 1:

The answer is going to be A

Question 2:

The answer is A

I hope this helps

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7x + 31= 8x- 1 (27x+3) - 3

Tresset [83]

AnswEr :

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The value of q is -1.42

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______________________

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➤ How to solve ?

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That's quite easy but you need to recall the BODMAS rule .

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BODMAS rule states the correct sequence to solve an equation . First we need to solve the bracket part then solve if any of is present moving further to division then multiplication carrying with addition atlast subtraction

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In this equation we will solve the bracket then we will apply further BODMAS rule

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SolutiOn :

➠ 7x + 31 = 8x - 1 ( 27x + 3 ) -3

➠ 7x + 31 = 8x - 27x - 3 - 3

Now, we will bring the variable on left hand side and constants on right hand side

➠ 7x - 8x + 27x = - 31 - 3 - 3

➠ 26x = -37

➠ x = -37/ 26

➠ x = - 1.42

∴ The value of x is -1.42 .

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3 0

3 years ago

8 times the sum of a number and 26 is less than 304.

Jlenok [28]

Answer:

x < 12

Step-by-step explanation:

So 8 times the sum of a number and 26 is less than 304. To find the number, lets write a equation where the "number" is x.
8 times the sum of a number and 26 can be written as 8 * x+26, however since the sum of x and 26 are being multiplied, we write this as 8(x+26). Since 8 times the sum of a number and 26 is less than 304, we set 8(x+26) to < 304. This gives us our equation:

8(x+26) < 304

Lets start to solve for x by dividing by 8, giving us:

x+26 < 38

Now lets isolate x by subtracting 26 from both sides, which gives us our answer:

x < 12

So x is less than 12.

Hope this helps!

7 0

1 year ago

Given sinx=3/5 and x is in quadrant 2, what is the value of tan(x/2)

xxMikexx [17]

X is in the second quadrant means that x/2 is in the first quadrant.

Consider the right triangle drawn in the figure. Let tan(x/2)=a.

Then, let the length of the opposite side to x/2 be a, the adjacent side be 1 and the hypotenuse be square root of a squared +1, as shown in the figure.

sin(x/2)=|opp side|/ |hypotenuse| = $\frac{a}{ \sqrt{ a^{2}+1 } }$

cos (x/2) = |adj side|/ |hypotenuse| = $\frac{1}{ \sqrt{ a^{2}+1 } }$

from the famous identity: sin(2a)=2sin(a)cos(a), we have:

2sin(x/2)cos (x/2)=sin(x)

thus

$2* \frac{a}{ \sqrt{ a^{2}+1 } }*\frac{1}{ \sqrt{ a^{2}+1 } }= \frac{3}{5}$

$2* \frac{a}{ a^{2}+1 }= \frac{3}{5}$

$10a=3 a^{2} +3$

$3 a^{2}-10a +3=0$

(3a-1)(a-3)=0

thus a=1/3 or a=3

thus tan(x/2)=1/3 or tan(x/2)=3

Answer: {1/3, 3}