Answer:
The length of the side of the triangle is 10 inches.
Step-by-step explanation:
Let p = perimeter of the equilateral triangle
Let P = perimeter of the square
Let s = length of side of the triangle
Let S = length of side of the square
"The perimeter of an equilateral triangle is 6 inches more than the perimeter of a square"
p = P + 6 Equation 1
"the side of the triangle is 4 inches longer than the side of the square"
s = S + 4 Equation 2
We have 2 equations and 4 unknowns. We need two more equations. We use the definition of perimeter to get the other two equations.
For an equilateral triangle,
p = 3s Equation 3
For a square,
P = 4S Equation 4
Substitute p and P of Equation 1 with equations 3 and 4. Then write equation 2.
3s + 4S = 6
s = S + 4
Now we have a system of 2 equations in 2 unknowns. We can solve for s and S. We can use the substitution method. Solve the second equation for S.
S = 4 - s
Substitute S = 4 - s into equation 3s + 4S = 6.
3s + 4(4 - s) = 6
3s + 16 - 4s = 6
-s = -10
s = 10
Answer: The length of the side of the triangle is 10 inches.
Answer:
The first and third quartile of the wingspans are 116.9 cm and 133.1 cm respectively.
Step-by-step explanation:
The first and third quartile of a normal distribution are:
The information provided is as follows:
Compute the first and third quartile of the wingspans as follows:
Thus, the first and third quartile of the wingspans are 116.9 cm and 133.1 cm respectively.
8640 square inches are in 60 feet
Answer:
1370754
Step-by-step explanation:
From what I can see, you are probably studying combinations and permutations at the moment. Since this is a question about how many groups of five can be produced from a sample size of 46, the groups are random and not in order, which may rule for us to use the combination formula.
Once you compute this, this answer is basically saying that 1370754 groups of 5 can be created from a sample size of 46
