Answer:
Explanation:
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In this case, the chemical reaction between magnesium and oxygen to yield magnesium oxide is:
In such a way, for 0.144 g of magnesium reacting with sufficient oxygen, the mass of magnesium oxide, whose molar mass is 40.3 g/mol (2:2 mole ratio) turns out:
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C6H12O6 -------> 6 C + 6 H20
moles C6H12O6 = ( 1745 g ) / ( 180 g/mol ) = 96.94 mol C6H12O6
mol C produced = ( 96.94 mol C6H12O6 reacted ) ( 6 mol C made / mol C6H12O6 reacted )
mol C produced = 58.17 moles C produced <-----------------------
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The elements can also be classified into the main-group elements (or representative elements) in the columns labeled 1, 2, and 13–18; the transition metals in the columns labeled 3–12; and inner transition metals in the two rows at the bottom of the table (the top-row elements are called lanthanides and the bottom-row ...