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leonid [27]
3 years ago
6

A 13-gram rubber stopper is attached to a 0.93-meter

Chemistry
1 answer:
makkiz [27]3 years ago
6 0
<h3>Answer:</h3>

The centripetal acceleration is 26.38 m/s²

<h3>Explanation:</h3>

We are given;

  • Mass of rubber stopper = 13 g
  • Length of the string(radius) = 0.93 m
  • Time for one revolution = 1.18 seconds

We are required to calculate the centripetal acceleration.

To get the centripetal acceleration is given by the formula;

Centripetal acc = V²/r

Where, V is the velocity and r is the radius.

Since time for 1 revolution is 1.18 seconds,

Then, V = 2πr/t, taking π to be 3.142 ( 1 revolution = 2πr)

Therefore;

Velocity = (2 × 3.142 × 0.93 m) ÷ 1.18 sec

             = 4.953 m/s

Thus;

Centripetal acceleration = (4.953 m/s)² ÷ 0.93 m

                                        = 26.38 m/s²

Hence, the centripetal acceleration is 26.38 m/s²

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