Answer:
Step-by-step explanation:
Given
5 tuples implies that:
implies that:
Required
How many 5-tuples of integers 
are there such that
From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.
Also considering that repetition is allowed: This implies that, a number can be repeated in more than 1 location
So, there are n + 4 items to make selection from
The selection becomes:
Expand the numerator
<u><em>Solved</em></u>
-4 (x - 5) + 3 (a - 7)
First, expand your problem. / Your problem should look like: -4x + 20 + 3a - 21
Second, simplify. / Your problem should look like: -4x + 3a - 1
Answer: -4x + 3a - 1 (C)
Using the triangle of pascal we have that the expression equivalent to (x + y) ^ 6 is given by:
x ^ 6 + 6x ^ 5y + 15x ^ 4y ^ 2 + 20x ^ 3y ^ 3 + 15x ^ 2y ^ 4 + 6xy ^ 5 + y ^ 6
Therefore, the coefficients of the expansion are given by:
1, 6, 15, 20, 15, 6, 1
Answer:
The coefficients corresponding to k = 0, 1, 2, ..., 6 in the expansion of (x + y) ^ 6 are 1, 6, 15, 20, 15, 6, 1
Answer:
thirty
Step-by-step explanation:
