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3 years ago

Evaluate and simplify 2ab-1/3e-3d

Mathematics

1 answer:

nikklg [1K]3 years ago

8 0

Answer: 2ab - e/3 - 3d

Step-by-step explanation:

2ab - 1/3e - 3d

= 2ab - 1e/3 - 3d

= 2ab - e/3 - 3d

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Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> In x = 3

mixer [17]

Answer:

The solution is:

$x = e^{3} = 20.09$

Step-by-step explanation:

The first step to solve this equation is placing everything with the logarithmicto one side of the equality, and everything without the exponential to the other side. So

$\ln{x} = 3$

It already is in the desired format.

Now, we have that, since e and ln are inverse operations

$e^{\ln{a}} = a$

So, we apply the exponential to both sides of the equality

$e^{\ln{x}} = e^{3}$

$x = e^{3} = 20.09$

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3 years ago

28264855 round to nearsest 100

BaLLatris [955]

<span>28 , 264 , 900 .

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4 years ago

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En un triangulo rectangulo ABC (B=90) REDUCE:

Dimas [21]

Answer:

puc provar, però no sé lemme see

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3 years ago

Let V be the volume of the solid obtained by rotating about the y-axis the region bounded y = 4x and y = x2/4 . Find V by slicin

aliya0001 [1]

Answer:

Step-by-step explanation:

Consider the graphs of the $y = 4x$ and $y = \frac{x^{2} }{4}$ .

By equating the expressions, the intersection points of the graphs can be found and in this way delimit the area that will rotate around the Y axis.

$4x = \frac{x^{2} }{4} \\ x^{2} = 16x \\ x^{2} - 16x = 0 \\ x(x-16) = 0$ then $x=0$ o $x=16$ . Therefore the integration limits are:

$y = 4(0) = 0$ and $y = 4(16) = 64$

The inverse functions are given by:

$x = 2 \sqrt{y}$ and $x = \frac{y}{4}$ . Then

The volume of the solid of revolution is given by:

$\int\limits^{64}_ {0} \, [2\sqrt{y} - \frac{y}{4}]^{2} dy = \int\limits^{64}_ {0} \, [4y - y^{3/2} + \frac{y^{2}}{16} ]\ dy = [2y^{2} - \frac{2}{5}y^{5/2} + \frac{y^{3}}{48} ]\limits^{64}_ {0} = 546.133 u^{2}$

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4 years ago

Please help! Will give brainliest answer!

Harrizon [31]

I have a strong felling the answer is the fourth shoice according to my calculations.

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3 years ago