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mina [271]
3 years ago
11

Two​ cars, 540 kilometers​ apart, begin driving toward each other on a​ long, straight highway. one car travels 75 kilometers pe

r hour and the other 105 kilometers per hour. at the same​ time, a​ canary, starting on one​ car, flies back and forth between the two cars as they approach each other. if the canary flies 100 kilometers per hour and spends no time to turn around at each​ car, how far has it flown when the cars​ collide?
Mathematics
1 answer:
Elodia [21]3 years ago
5 0

One car travels at a speed of 75 kilometers per hour and the other car travels at a speed of 105 kilometers per hour.

Since both the cars are travelling towards each other their combined speed will be: 75+105=180 km/h.

Now, since the distance between the cars to start with is 540 km. Therefore, the time taken before the cars collide is:

t=\frac{540}{180} =3 hours.

Now, the speed of the canary is 100 km/h.

Therefore, the Canary flies flies for (100 km/h)x(3 hours) = 300 km before the cars collide.


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Now, \sqrt{x^2}=|x| in general. But since we want our substitution x=5\sin\theta to be invertible, we are tacitly assuming that we're working over a restricted domain. In particular, this means \theta=\sin^{-1}\dfrac x5, which implies that \left|\dfrac x5\right|\le1, or equivalently that |\theta|\le\dfrac\pi2. Over this domain, \cos\theta\ge0, so \sqrt{\cos^2\theta}=|\cos\theta|=\cos\theta.

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