3 years ago

I need help w this, thanks

Mathematics

2 answers:

Rama09 [41]3 years ago

3 0

60 I believe I hope this helps if it was right :)

arlik [135]3 years ago

3 0

It is 60
Hope it helped you

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Find all the zeroes of the equation 2x^4-5x^3+53x^2-125x+75=0

Marizza181 [45]

$- 5i \: \: \: 5i \: \: \: \: 1 \: \: \: \: 1.5$

6 0

3 years ago

Read 2 more answers

1/a+1/b=c solve for b how would i do this

olganol [36]

a cheap way to go about it is, let's do away with the denominators, and we'll do so by simply multiplying both sides by the the LCD of all fractions, in this case, that'd be "ab", so we multiply both sides by "ab".

$\bf \cfrac{1}{a}+\cfrac{1}{b}=c\implies\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{ab}}{ab\left( \cfrac{1}{a}+\cfrac{1}{b} \right)=ab(c)}\implies b+a=abc \\\\\\ a=abc-b\implies a=\stackrel{\textit{common factor}}{b(ac-1)}\implies \cfrac{a}{ac-1}=b$