Question

Consider the vector b⃗ b→b_vec with length 4.00 mm at an angle 23.5∘∘ north of east. What is the y component bybyb_y of this vector?

Answer 1

Answer:

• $\large\boxed {1.59 mm}$

Explanation:

1. Given vector:

• length: 4.00 mm = magnitude of the vector
• angle: 23.5º north of east = 23.5º from the x-axys (counterclockwise)

2. y-component

The y-component may be determined using the sine ratio, the angle from the x-axys (counterclockwise direction), and the magnitude of the vector.

• sine (23.5º) = y-component / magnitude

• y-component = magnitude × sine (23.5º) = 4.00 mm × sine (23.5º) = 1.59 mm.

• $\large\boxed{y-component = 1.59 mm}$