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dybincka [34]
3 years ago
7

The density of an object is defined as mass per unit volume. Mathematically we write that:

Chemistry
2 answers:
Snezhnost [94]3 years ago
4 0
M=DxV V=M/D
(answer limit etcetcetc)))))
GuDViN [60]3 years ago
3 0
For the mass M=V x D

for the volume V= M / D
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Ana drives at a speed of 175m/s. she recorded a distance of 2km. Find the time.
pantera1 [17]

The time it took her to drive 2 km is 11.43 seconds, because sonverting kilometers to meters, it is 1000 meters to every kilometer, and she travels 2 kilometers, which is two-thousand meters. Then to find the time you need to divide the time by the speed, and with that you get 11.4285714286, or 11.43 seconds.

6 0
3 years ago
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What is the name of the ionic compound Csmc010-1.jpgS? cesium sulfur cesium sulfide dicesium sulfur dicesium sulfide
nika2105 [10]
Answer is: cesium sulfide.
Formula for ionic compound is: Cs₂S.
Ionic compound <span>electrically </span>neutral, cesium has charge +1 (2· (+1) = +2) and sulfur has charge -2.
Cesium sulfide is whide powder, soluble in water, pyrophoric in dry air, reductant.
5 0
3 years ago
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1. When this equation is balanced, Fe + 02 -.--&gt; Fe203, what is the
Vilka [71]

Fe + O2 → Fe2O3

After balancing the eq.

4Fe + 3O2 → 2Fe2O3

Hope this will help u mate :)

4 0
3 years ago
The freezing point of ethanol, CH3CH2OH, is -117.300 °C at 1 atmosphere. Kf(ethanol) = 1.99 °C/m
MAXImum [283]

Answer : The molecular weight of this compound is 891.10 g/mol

Explanation :  Given,

Mass of compound = 12.70 g

Mass of ethanol = 216.5 g

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T_f^o-T_f=i\times T_f\times\frac{\text{Mass of compound}\times 1000}{\text{Molar mass of compound}\times \text{Mass of ethanol}}

where,

\Delta T_f = change in freezing point

T_f^o = temperature of pure ethanol = -117.300^oC

T_f = temperature of solution = -117.431^oC

K_f = freezing point constant of ethanol = 1.99^oC/m

i = van't hoff factor = 1   (for non-electrolyte)

m = molality

Now put all the given values in this formula, we get

(-117.300)-(-117.431)=1\times 1.99^oC/m\times \frac{12.70g\times 1000}{\text{Molar mass of compound}\times 216.5g}

\text{Molar mass of compound}=891.10g/mol

Therefore, the molecular weight of this compound is 891.10 g/mol

7 0
3 years ago
Balance the following oxidation-reduction reactions, which take place in acidic solution, by using the "half-reaction" method.
LuckyWell [14K]
First identify which is being oxidized and reduced. In this case, the Mg is being oxidized and the Hg is being reduced. 

Mg --> Mg+2 
 
<span>Hg+2 --> Hg+1 
</span>
Then you have to balance each half reaction first with electrons before adding them together in one equation

Mg ⇒ Mg^{+2}  +  2e^{-1}

and

2Hg^{+2} + 2e^{-1} ⇒ Hg_{2} ^{+2}
 
and then combine them together to form 

Mg + 2 Hg^{+2} + 2e ⇒ Mg^{+2} + 2e ^{-} + 2 Hg^{+1} + 2 e^{-}

It isn't necessary to keep the electrons but its essential to know how many there are in order to know how many are in the equation in order to calculate the reaction energy. Note: A<span>dd H+ and H2O to balance the H's and O's in acidic solution if needed.</span>
8 0
3 years ago
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