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dybincka [34]
3 years ago
7

The density of an object is defined as mass per unit volume. Mathematically we write that:

Chemistry
2 answers:
Snezhnost [94]3 years ago
4 0
M=DxV V=M/D
(answer limit etcetcetc)))))
GuDViN [60]3 years ago
3 0
For the mass M=V x D

for the volume V= M / D
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The calcium concentration must be greater outside the cell than inside the cell.

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A student calculates the mass of a piece of copper to be 8.3 grams. The actual mass of the copper is 10. grams. What is the perc
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17%

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2. A convergent boundary is
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3 years ago
Nitrogen dioxide is one of the many oxides of nitrogen (often collectively called "NOx") that are of interest to atmospheric che
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Answer:

Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time is 0.82 atm.

Explanation:

2NO_2(g)\rightleftharpoons N_2O_4(g)

Initially

3.0 atm                 0

At equilibrium

(3.0-2p)                 p

Equilibrium partial pressure of NO_2=2.1atm=3.0-2p

p = 0.45 atm

The value of equilibrium constant wil be given by :

K_p=\frac{p_{N_2O_4}}{(p_{NO_2})^2}=\frac{p}{(3.0-2p)^2}

K_p=\frac{0.45}{(2.1)^2}=0.10

After addition of 1.5 atm of nitrogen dioxide gas equilibrium reestablishes it self :

2NO_2(g)\rightleftharpoons N_2O_4(g)

After adding 1.5 atm of NO_2:

(2.1+1.5) atm                0.45 atm

At second equilibrium:'

(3.6-2P)                     (0.45+P)

The expression of equilibrium can be written as:

K_p=\frac{p'_{N_2O_4}}{(p'_{NO_2})^2}

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Solving for P:

P = 0.37 atm

Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time:

= (0.45+P) atm = (0.45 + 0.37 )atm = 0.82 atm

Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time is 0.82 atm.

5 0
3 years ago
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