Answer:
2 K + 1 CrBr2 yield 2 KBr + 1 Cr
Explanation:
Answer:
Mass = 25.08 g
Explanation:
Given data:
Volume of fluorine = 29.6 L
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Mass of fluorine = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
n = PV/RT
n = 1 atm × 29.6 L / 0.0821 atm.L/ mol.K × 273.15 K
n = 1.32 mol
Mass of fluorine:
Mass = number of moles × molar mass
Mass = 1.32 mol ×19 g/mol
Mass = 25.08 g
Answer:
False
Explanation:
Laboratory synthesis of aspirin is done by the acetylation of salicylic acid with the help of acetic anhydride .
As , the acid anhydride is very sensitive to moisture , as it can hydrolyze into two molecules of acids,
Hence , the reaction involving acid anhydride are conducted in anhydrous solvents .
Hence ,
if water is present in the glassware then , some of the acetic anhydride is wasted , Which in turns reduces the yield than that expected .
Complete question:
Write the condensed formula from left to right, starting with (CH3)x where x is a number.
See attached image for the structure formula of the compound
Answer:
(CH₃)₂CHC(CH₃)₃ named as 2,2,3-Trimethylbutane
Explanation:
If we number the longest chain of the carbon starting from the left, we will observe that there are four carbons in the straight chain as shown in the image.
Starting from first carbon from the left of the carbon chain, at carbon number number 2, there two alkyl group, that is two methyl (CH3 is two). Also at carbon number 3, there are three alkyl group, that is three methyl (CH3 is three).
The condensed formula will be written as;
(CH₃)₂CHC(CH₃)₃
This compound is named as 2,2,3-Trimethylbutane, an isomer of Heptane
Answer is: molarity is 0,155 M.
V(solution) = 90,0 mL = 0,09 L.
ω(NaCl) = 0,92% ÷ 100% = 0,0092.
d(solution) = 1 g/mL.
m(solution) = V(solution) · d(solution).
m(solution) = 90 mL · 1 g/mL = 90 g.
m(NaCl) = 90 g · 0,0092 = 0,828 g.
n(NaCl) = 0,828 g ÷ 58,4 g/mol.
n(NaCl) = 0,014 mol.
c(solution) = 0,014 mol ÷ 0,09 L.
c(solution) = 0,155 mol/L.
