A student calculates the mass of a piece of copper to be 8.3 grams. The actual mass of the copper is 10. grams. What is the perc
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Answer: Mass of required to form 930 kg of iron is 1328 kg
Explanation:
To calculate the number of moles, we use the equation:
.....(1)
For iron:
Given mass of iron = 930 kg = 930000 g (1kg=1000g)
Molar mass of iron = 56 g/mol
Putting values in equation 1, we get:
The chemical equation for the production of iron follows:
By Stoichiometry of the reaction:
2 moles of iron are produced by = 1 mole of
So, 16607 moles of iron will be produced by = of
Now, calculating the mass of from equation 1, we get:
Mass of =
Thus mass of required to form 930 kg of iron is 1328 kg
<h2>The compound formed is NaCl and 
</h2>
Explanation:
PART 1:
- Atomic number of sodium is 11.
- Sodium(Na, Z = 11, Group 1A) will lose 1 electron to become
which is isoelectronic to Neon (Ne ,Z = 10).
- The symbol for the sodium ion is
.
- Chlorine atom (
, Z = 17, Group 7A or 17) gains 1 elecron to be isoelectronic to neon.
- The symbol for the compound formed is NaCl.
- PART 2:
- Atomic number of calcium is 20
- Calcium(Ca, Z = 20 ,Group 2A) will lose two electrons to become
which is isoelectronic to argon.
- The symbol for the ion is
- Two chlorine atoms (Cl, Z = 17, Group 7A or 17) each gains one electron to be isoelectronic to argon(Z = 18)
- The symbol for the compound formed is