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natita [175]
3 years ago
8

Which of the following best describes biogeochemical cycles? A. They cycle elements through the biotic and abiotic components of

an ecosystem. B. They cycle elements through the plants and trees of an ecosystem C. They cycle elements through the plants and soil of an ecosystem. D.all of the above
Chemistry
1 answer:
Ad libitum [116K]3 years ago
6 0

Answer:

A. They cycle elements through the biotic and abiotic components of an ecosystem.

Explanation:

Chemical elements such as nitrogen, carbon, phosphorus etc. moves between the living and non-living parts of an ecosystem in the biosphere. The cycle of these elements between these counterparts (abiotic and biotic) is referred to as the BIOGEOCHEMICAL CYCLE.

Firstly, the biotic components of an ecosystem refers to the living organisms such as plants, animals, microbes etc while the abiotic components are the non-living parts such as soil, water etc. Therefore, according to the description given in the options, option A describes what a BIOGEOCHEMICAL CYCLE best.

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3 years ago
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_____?or current flow, can be thought of as a faucet being turned on and water flowing.
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Answer: Circuit Flow

Explanation:

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3 years ago
Lithium diorganocopper (Gilman) reagents are prepared by treatment of an organolithium compound with copper(I) iodide. Decide wh
Ann [662]

Answer:

See explanation and image attached

Explanation:

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7 0
2 years ago
a mixture containing 21.4 g of ice. (0.00 c) and 75.3 g of water (55.3 c) is placed in an insulatated container
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7 0
3 years ago
YOU DO:
mihalych1998 [28]

Answer:

67.1%

Explanation:

Based on the chemical equation, if we determine the moles of sodium carbonate, we can find the moles of NaHCO₃ that reacted and its mass, thus:

<em>Moles Na₂CO₃ - 105.99g/mol-:</em>

6.35g * (1mol / 105.99g) = 0.0599 moles of Na₂CO₃ are produced.

As 1 mole of sodium carbonate is produced when 2 moles of NaHCO₃ reacted, moles of NaHCO₃ that reacted are:

0.0599 moles of Na₂CO₃ * (2 moles NaHCO₃ / 1 mole Na₂CO₃) = 0.1198 moles of NaHCO₃

And the mass of NaHCO₃ in the sample (Molar mass: 84g/mol):

0.1198 moles of NaHCO₃ * (84g / mol) = 10.06g of NaHCO₃ were in the original sample.

And percent of NaHCO₃ in the sample is:

10.06g NaHCO₃ / 15g Sample * 100 =

<h3>67.1%</h3>
7 0
3 years ago
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