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3 years ago

What is a polynomial function in standard form with zeros 1,2,3,and -3?

Mathematics

1 answer:

konstantin123 [22]3 years ago

8 0

Answer:

option 3 is right.........

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Which of the following coordinates exists on the line y = 2x - 4?

Artyom0805 [142]

The coordinate is (1,-2)

3 0

3 years ago

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Help!! If anyone could help, I’ll give Brainly! :) thank you so much

OLga [1]

9514 1404 393

Answer:

$50

Step-by-step explanation:

The compounding period is 1 year, and the period of concern is 1 year. This means the simple interest formula will tell the answer to the question.

I = Prt

I = ($5000)(0.01)(1) . . . . . r = annual rate; t = years

I = $50

The interest earned in the account is $50.

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3 years ago

I need help because idk bbbbbbbbbbbbbbbb

MArishka [77]

Answer:I think it's the second answer

Step-by-step explanation:

Add up all the numbers on the outside of the house to get your answer.

6 0

3 years ago

*PLEASE HELP MEEEEEE* You throw a dart at the board shown. Your dart is equally likely to hit any point inside the square board.

yawa3891 [41]

Answer:

19.63%

Step-by-step explanation:

The probability of scoring 8 points is the probability of getting a dart into the green circle.

That probability is equivalent to the area of the circle divided by the total area of the square board.

The area of the circle according to $A=\pi*r^2$ , is $25\pi$ cm squared

The area of the whole square board is one side squared: 20 squared = 400 cm squared

The probability is therefore equal to $25\pi/400 = \pi/16=0.19634=19.63%$ %

8 0

3 years ago

A polymer is manufactured in a batch chemical process. Viscosity measurements show that it is approximately normally distributed

PilotLPTM [1.2K]

Answer: (751.05, 766.95)

Step-by-step explanation:

We know that the confidence interval for population mean is given by :-

$\overline{x}\pm z*\dfrac{\sigma}{\sqrt{n}}$ ,

where $\sigma$ =population standard deviation.

$\overline{x}$ = sample mean

n= sample size

z* = Two-tailed critical z-value.

Given : $\sigma= 20$

n= 42

$\overline{x}=759$

We know that from z-table , the two-tailed critical value for 99% confidence interval : z* =2.576

Now, the 99% confidence interval around the true population mean viscosity :-

$759\pm (2.5760)\dfrac{20}{\sqrt{42}}\\\\=759\pm (2.5760)(3.086067)\\\\=759\pm7.9497=(759-7.9497,\ 759+7.9497)\]\\=(751.0503,\ 766.9497)\approx(751.05,\ 766.95)$

∴ A 99% confidence interval around the true population mean viscosity : (751.05, 766.95)

3 0

3 years ago