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Licemer1 [7]
3 years ago
14

In shipment of 850 widgets, 32 are found to be detective. At this rate, how many detective widgets could be expected in 22,000 w

idgets? Around the nearest whole number
Mathematics
1 answer:
cluponka [151]3 years ago
4 0

Answer:

The number of detective widgets out of 22,000 widgets is 828 widgets

Step-by-step explanation:

Given as :

The total number of widgets = 850

The number of detective widgets out of 850 = 32

Now,

∵ Out of 850 widgets , the number of detective widgets = 32

SO,Out of 1 widgets , the number of detective widgets = \frac{32}{850}

∴ Out of 22,000 widgets , the number of detective widgets = \frac{32}{850} × 22,000

Or, Out of 22,000 widgets , the number of detective widgets = 828.23

Hence, The number of detective widgets out of 22,000 widgets is 828 widgets Answer

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For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12
notsponge [240]
The binomial distribution is given by, 
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They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = (^{100}C_{x})(0.2)^{x} (0.8)^{100-x}
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∴ P(X≤12) = (^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1} + (^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3} + (^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5} + (^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7} + (^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9} + (^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11} + (^{100}C_{12})(0.2)^{12} (0.8)^{100-12}


Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
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4 years ago
Find the vertex of the graph of the function.
lapo4ka [179]

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Explanation:

Te standard form of the parabola is,

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(6)

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