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Licemer1 [7]
3 years ago
14

In shipment of 850 widgets, 32 are found to be detective. At this rate, how many detective widgets could be expected in 22,000 w

idgets? Around the nearest whole number
Mathematics
1 answer:
cluponka [151]3 years ago
4 0

Answer:

The number of detective widgets out of 22,000 widgets is 828 widgets

Step-by-step explanation:

Given as :

The total number of widgets = 850

The number of detective widgets out of 850 = 32

Now,

∵ Out of 850 widgets , the number of detective widgets = 32

SO,Out of 1 widgets , the number of detective widgets = \frac{32}{850}

∴ Out of 22,000 widgets , the number of detective widgets = \frac{32}{850} × 22,000

Or, Out of 22,000 widgets , the number of detective widgets = 828.23

Hence, The number of detective widgets out of 22,000 widgets is 828 widgets Answer

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Step-by-step explanation:

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Quincy says that 3 is a good estimate for 3.4 X 0.09, is he correct? Why?
lord [1]
<span>Quincy says that 3 is a good estimate for 3.4 X 0.09, is she correct? Why?
When we say estimates meaning it is not the exact answer but close to what is the exact.
Now, if Quincy estimated 3 as the product of 3.4 * .09, then let’s check if she has the correct estimates.
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3 years ago
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Eddi Din [679]

Answer:

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Step-by-step explanation:


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3 years ago
Camryn practices the trumpet every 11^\text{th}11
Snowcat [4.5K]

Answer:

in 33 days

Step-by-step explanation:

Trumpet practice is every 11 days. Flute practice is every 3 days.

You need the Least Common Multiple (the LCM) of the two numbers, 3 and 11.

Since 3 and 11 are prime, the LCM of 3 and 11 is their product.

LCM = 3 * 11 = 33

Answer: in 33 days

You can also solve this by listing multiples of 3 and 11 until you find the smallest number that is a multiple of both 3 and 11.

Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, ...

Multiples of 11: 11, 22, 33, 44, ...

The smallest multiple of both 3 and 11 is the smallest number that shows in both lists. It is 33.

4 0
3 years ago
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