This allows the water cycle to take hold. Transferring water to places all across the globe, adding minerals and purifying other water In the process.
Answer:
The compound which will precipitate first will be AgI with 
Explanation:
In order to precipitate a salt solution the ionic product of salt must exceed the solubility product.
Given:
Ksp of AgI = 
Ksp of PbI2= 
As Ksp of AgI is very low it will precipitate faster than lead iodide.
Now, higher the concentration of AgI solution taken faster its precipitation.
In the given choice the highest concentration solution of AgI is 
What are you trying to ask??????
There are 4 significant figures.
zeros after the decimal point are not significant
Answer:
Chloride ion is a strong nucleophile and bromide is a good leaving group. The major product of treating (S)-2-bromobutane with NaCl in CH3C(O)CH3 (acetone) is _________. (1S,2R)-1-chloro-2-bromobutane cis-2-butene (1R,2S)-1-chloro-2-bromobutane (S)-2-chlorobutane trans-2-butene (R)-2-chlorobutane
Explanation:
The reaction of (S)-2-bromobutane with NaCl in CH3C(O)CH3 (acetone) forms the following product:
The answer is (R)-2-chlorobutane.
The reaction take splace through
mechansim and inversion in configuration happens.