Answer:
4L
Explanation:
To obtain the volume of O2 at stp, first, we need to determine the number of mole of O2.
From the question given above,
Mass of O2 = 5.72g
Molar Mass of O2 = 32g/mol
Number of mole =Mass/Molar Mass
Number of mole of O2 = 5.72/32
Number of mole of O2 = 0.179 mole
Now, we can calculate the volume of O2 at stp as follow:
1 mole of a gas occupy 22.4L at stp.
Therefore, 0.179 mole of O2 will occupy = 0.179 x 22.4 = 4L
Therefore, the volume occupied by the sample of O2 is 4L
We classify them as follows:
1. 1 mol NaCl (s) à 1 mol NaCl(l)
C Molar heat of fusion; endothermic
2. C4H10 O(l) à C4H10O (g)
B Molar heat of vaporization; endothermic
3. H2O(g) à H2O (l)
D Molar heat of condensation; exothermic
4. 1 mol NaCl(s) + 3.88 kJ/molà 1 mol NaCl(aq)
A Molar heat of solution; endothermic
Answer:
The large the atomic radius the more the metallic character of elements
Explanation:
The atomic radius is related to the metallic character in a way that the larger the atomic radius, the more metallic a body becomes.
Therefore, as we go down a group, metallic character increases.
- Metallic character relies on the ability and willingness of an atom to share its valence electrons.
- As the size of an atom becomes large, the more metallic it is and the more its metallic character.
- In some other cases this character is known as electropositivity.
