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Nostrana [21]
3 years ago
15

Calculate the mass of butane needed to produce 96.7 g of carbon dioxide

Chemistry
1 answer:
ella [17]3 years ago
5 0
<span>31.9 grams butane needed to produce 96.7 grams CO2

</span>
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Juan inflates a balloon and then releases its end to let the balloon go free as air comes out. The balloon then flies around the
MArishka [77]
Here is the correct option: According to Newton's third law of motion, the balloon is pushed forward as the air is forced out.  Newton's third law of motion states that for every action there is an equal and opposite reaction. This means that in every interaction, there is a pair of force that is acting on the interacting objects, the size of the force on the first object is equal to the size of the force on the second object.
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3 years ago
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Medicinal “ether" is produced when ethyl alcohol is treated with an acid. How many grams of
DochEvi [55]

Answer:

34.3 g

Explanation:

Step 1: Write the balanced equation

2 CH₃CH₂OH ⇒ CH₃CH₂OCH₂CH₃ + H₂O

Step 2: Calculate the moles corresponding to 50.0 g of CH₃CH₂OH

The molar mass of CH₃CH₂OH is 46.07 g/mol.

50.0 g × 1 mol/46.07 g = 1.09 mol

Step 3: Calculate the theoretical moles of CH₃CH₂OCH₂CH₃ produced

The molar ratio of CH₃CH₂OH to CH₃CH₂OCH₂CH₃ is 2:1. The moles of CH₃CH₂OCH₂CH₃ theoretically produced are 1/2 × 1.09 mol = 0.545 mol.

Step 4: Calculate the real moles of CH₃CH₂OCH₂CH₃ produced

The percent yield of the reaction is 85%.

0.545 mol × 85% = 0.463 mol

Step 5: Calculate the mass corresponding to 0.463 moles of CH₃CH₂OCH₂CH₃

The molar mass of CH₃CH₂OCH₂CH₃ is 74.12 g/mol.

0.463 mol × 74.12 g/mol = 34.3 g

6 0
3 years ago
Put the following in the correct chronological order from what happened first to what happened last.
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3 years ago
How many Ni atoms are in 3.6 mol of Ni
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I believe that the answer is 1.8^24 of Ni atoms in 3.6 mol of Ni.

Hope this helps. :)

6 0
3 years ago
Help me with 4,5 plz
Helen [10]
The answer to 4 is A.                                              
The answer to 5 is C.
7 0
3 years ago
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