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MAVERICK [17]
3 years ago
8

Photosynthesis can be represented by 6CO2(g)+6H2O(l)⇌C6H12O6(s)+6O2(g) Which of the following will be false when the photosynthe

sis reaction reaches equilibrium? The rate of formation of O2 is equal to the rate of formation of CO2. The concentration of O2 will begin decreasing. The concentrations of CO2 and O2 will not change. The concentrations of CO2 and O2 will be equal.
Chemistry
2 answers:
frutty [35]3 years ago
6 0

Answer:

The concentration of O2 will begin decreasing.

Explanation:

Luba_88 [7]3 years ago
6 0

Answer: Option (b) and (d) are the correct answer.

Explanation:

It is known that at equilibrium, the rate of forward reaction is equal to the rate of backward reaction.

Therefore, it means that at equilibrium the concentration of reactants is equal to the concentration of products.

Hence, in the given reaction also the rate of formation of O_2 is equal to the rate of formation of CO_2.

And, at equilibrium there will be no decrease or increase in the concentration of any specie involved in the reaction.

Also, the concentrations of CO_{2} and O_{2} will be equal.

Thus, we can conclude that the statement concentration of O_2 will begin decreasing, is false when the photosynthesis reaction reaches equilibrium.

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B

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True or false? An organism may play more than one role in a food web
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Using the principles of VSEPR theory, you can predict the geometry around any atom in any molecule, no matter how complex. Enant
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Explanation:

The O atom is sp3 in a water molecule, with two sigma bonds and two lone pairs of electrons like that in water. The steric integer is thus 4, and its structure is tetrahedral.

The C atom is sp hybridised into two identical bonds and two identical bonds in acetylene.

The steric integer is therefore 2 because only sigma bonds are engaged in deciding hybridization, and its structure is linear.

The C atom is sp2 hybridised in ethene with single pi bond and three sigma identical bonds.

Thus the steric integer is 3, and its structure is planar trigonal.

The C atom is sp2 hybridized in ethene, with one pi bond and three sigma identical bonds.

The steric integer would therefore be 3 and its structure is planar trigonal.

The O atom is sp3 in a water molecule with two bond pairs and two lone pairs of electrons like that. The steric integer is thus 4, and its structure is tetrahedral.

The C atom is sp3 in a methane ring, with 4 bond pairs and no solitary pairs of electrons like that. The steric integer is thus 4, and its structure is tetrahedral.

6 0
2 years ago
Which is the most explosive element?
UkoKoshka [18]

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2 years ago
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The heat of fusion AH, of ethyl acetate (C4H802) is 10.5 kinol. Calculate the change in entropy as when 398. g of ethy, acetate
Hitman42 [59]

<u>Answer:</u> The entropy change of the ethyl acetate is 133. J/K

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of ethyl acetate = 398 g

Molar mass of ethyl acetate = 88.11 g/mol

Putting values in above equation, we get:

\text{Moles of ethyl acetate}=\frac{398g}{88.11g/mol}=4.52mol

To calculate the entropy change for different phase at same temperature, we use the equation:

\Delta S=n\times \frac{\Delta H_{fusion}}{T}

where,  

\Delta S = Entropy change  = ?

n = moles of ethyl acetate = 4.52 moles

\Delta H_{fusion} = enthalpy of fusion = 10.5 kJ/mol = 10500 J/mol   (Conversion factor:  1 kJ = 1000 J)

T = temperature of the system = 84.0^oC=[84+273]K=357K

Putting values in above equation, we get:

\Delta S=\frac{4.52mol\times 10500J/mol}{357K}\\\\\Delta S=132.9J/K

Hence, the entropy change of the ethyl acetate is 133. J/K

7 0
2 years ago
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