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MAVERICK [17]
3 years ago
8

Photosynthesis can be represented by 6CO2(g)+6H2O(l)⇌C6H12O6(s)+6O2(g) Which of the following will be false when the photosynthe

sis reaction reaches equilibrium? The rate of formation of O2 is equal to the rate of formation of CO2. The concentration of O2 will begin decreasing. The concentrations of CO2 and O2 will not change. The concentrations of CO2 and O2 will be equal.
Chemistry
2 answers:
frutty [35]3 years ago
6 0

Answer:

The concentration of O2 will begin decreasing.

Explanation:

Luba_88 [7]3 years ago
6 0

Answer: Option (b) and (d) are the correct answer.

Explanation:

It is known that at equilibrium, the rate of forward reaction is equal to the rate of backward reaction.

Therefore, it means that at equilibrium the concentration of reactants is equal to the concentration of products.

Hence, in the given reaction also the rate of formation of O_2 is equal to the rate of formation of CO_2.

And, at equilibrium there will be no decrease or increase in the concentration of any specie involved in the reaction.

Also, the concentrations of CO_{2} and O_{2} will be equal.

Thus, we can conclude that the statement concentration of O_2 will begin decreasing, is false when the photosynthesis reaction reaches equilibrium.

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Molarity=\frac{n}{V_s}

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