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Sindrei [870]
2 years ago
13

Chromium (III) oxide reacts with hydrogen sulfide gas to form chromium (III) sulfide and water. To produce 421 g of cr2s3, how m

any moles of cr2o3 and grams of cr2o3 are required?
Chemistry
1 answer:
maw [93]2 years ago
6 0

Cr₂O₃ ( s ) + 3H₂S ( g ) → Cr₂S₃ ( s ) + 3H₂O ( l )

mol  Cr₂S₃ = 421 : 200.19 g/mol = 2.103

mol Cr₂O₃ ≈ mol Cr₂S₃ = 2.103 ( equivalent coefficient)

mass Cr₂O₃ = 2.103 x 151.99 g/mol = 319.63 gr

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How many moles of KBr will be produced from 10.51 moles of BaBr2?
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Answer:

21.02moles of KBr

Explanation:

Parameters given:

Number of moles BaBr₂ = 10.51moles

Complete reaction equation:

           BaBr₂ + K₂SO₄ → KBr + BaSO₄

Upon inspecting the given equation, we find out that the atoms are not balanced on both sides of the equation:

        The balanced equation is:

           BaBr₂ + K₂SO₄ → 2KBr + BaSO₄

From the equation:

     1 mole of BaBr₂ produces 2 moles of KBr

∴   10.51 moles of BaBr₂ will yield (2 x 10.51) moles = 21.02moles of KBr

7 0
3 years ago
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3 0
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Fiesta28 [93]
Oxygen and selenium both have 6 valence electrons. They're in the same group hope this helps
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