Chromium (III) oxide reacts with hydrogen sulfide gas to form chromium (III) sulfide and water. To produce 421 g of cr2s3, how m
any moles of cr2o3 and grams of cr2o3 are required?
1 answer:
Cr₂O₃ ( s ) + 3H₂S ( g ) → Cr₂S₃ ( s ) + 3H₂O ( l )
mol Cr₂S₃ = 421 : 200.19 g/mol = 2.103
mol Cr₂O₃ ≈ mol Cr₂S₃ = 2.103 ( equivalent coefficient)
mass Cr₂O₃ = 2.103 x 151.99 g/mol = 319.63 gr
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