Set the radicand in
√
x
−
5
x
-
5
greater than or equal to
0
0
to find where the expression is defined.
x
−
5
≥
0
x
-
5
≥
0
Add
5
5
to both sides of the inequality.
x
≥
5
x
≥
5
The domain is all values of
x
x
that make the expression defined.
Interval Notation:
[
5
,
∞
)
[
5
,
∞
)
Set-Builder Notation:
{
x
|
x
≥
5
}
{
x
|
x
≥
5
}
The range of an even indexed radical starts at its starting point
(
5
,
0
)
(
5
,
0
)
and extends to infinity.
Interval Notation:
[
0
,
∞
)
[
0
,
∞
)
Set-Builder Notation:
{
y
|
y
≥
0
}
{
y
|
y
≥
0
}
Determine the domain and range.
A. No
5 + 15 = 20
B. Yes
33/3 (33 ÷ 3) = 11
C. No
5 × 7 = 35
Answer: 1
Step-by-step explanation:
16 * 1/2 = 8
7x + 1 = 8
7x = 7
x = 1
Answer:
6
Step-by-step explanation:
mark me brainliest!!
Answer:
No we can consider A as single event. See the explanation below
Step-by-step explanation:
Let's define the event A as:
A=" Select a 4 from a standard deck of 52 cards"
We know that in a standard deck we have 4 different types of 4, spade, heart, diamond and club.
And by definition of simple event we need to have just one possible outcome in the experiment, and on this case we have 4 possible options for event A, so for this reason the event A can't be considered as simpl event.
