Answer:
Answer for the question :
"Consider a rectangular wing mounted in a low-speed subsonic wind tunnel. The wing model completely spans the test-section, so that the flow "sees" essentially an infinite wing. The wing has a NACA 23012 airfoil section and a chord of 0.23 m, where the lift on the entire wing is measured as 200 N by the wind tunnel force balance. Determine the angle of attack if the wing span, airflow pressure, temperature, and velocity are 2 m, 1 atm, 303 K, and 42 m/s, respectively. Refer to the Appendix graphs given below for standard values" is in the attachment.
Explanation:
Answer:
iv) It is 9x bigger than before
Explanation:
As the amplitudes of the new speakers add directly with the original one, taking into account the phase that they have, the composed amplitude of the sound wave is as follows:
At = A + 4A -2A = 3 A
The intensity of the wave, assuming it propagates evenly in all directions, is constant at a given distance from the source, and can be expressed as follows:
I = P/A
where P= Power of the wave source, A= Area (for a point source, is equal to the surface area of a sphere of radius r, where is r is the distance to the source along a straight line)
For a sinusoidal wave, the power is proportional to the square of the amplitude, so the intensity is proportional to the square of the amplitude also.
If the amplitude changes increasing three times, the change in intensity will be proportional to the square of the change in amplitude, i.e., it will be 9 times bigger.
So, the statement iv) is the right one.
Http://www.kyrene.org/cms/lib2/AZ01001083/Centricity/Domain/2932/Peppered%20Moth%20and%20Galapados%20Island%20PowerPoint.pptx
This should lead you to correct answer
Answer:
Direction of the electric force acting on the proton after it enters the electric field is along the positive y-axis.
Explanation:
In an electrical field electrical field lines goes from positive to negative. Therefore, electrical force vector is on exactly the same way with electrical field lines for a proton. Which means if the electrical field directed along the positive y-axis, electrical force for proton will be on the same way.