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sweet-ann [11.9K]
3 years ago
5

The function of the ossicles in the middle ear is to transmit the vibrations of the tympanic membrane caused by sound waves prop

agated in air to the fluid-filled cochlea. In doing so, the ossicles change the nature of the vibrations. The ear tries to conserve the energy in the wave I,
where v is the wave speed, cramster-equation-2010731130406341613664 is the density of the medium, cramster-equation-2010731131286341613668 is the frequency of the wave and A is the amplitude of the wave.
Calculate the magnitude of the change in A that occurs. The density of air and water is 1.3x10–3g/cm3 and 1.0g/cm3, respectively, and the velocity of sound is 331 m/s in air and 1410 m/s in water. The frequency of the wave remains constant as the wave propagates. (Hint: Begin with to find .)
Physics
1 answer:
Daniel [21]3 years ago
6 0
A I hope I helpedddd
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A student conducts an experiment in which a cart is pulled by a variable applied force during a 2sec time interval. In trial 1,
Harlamova29_29 [7]

Answer:

change of momentum does not depend on the mass of the cars, as the force and time are the same all vehicles have the same change of momentum

Explanation:

Let's look for the speed of the car

     F = m a

    a = F / m

We use kinematics to find lips

    v = v₀ + a t

    v = v₀ + (F / m) t

The moment is defined by

    p = m v

The moment change

    Δp = m v - m v₀

Let's replace the speeds in this equation

    Δp = m (v₀ + F / m t) - m v₀

    Δp = m v₀  + F t - m v₀  

    Δp = F t

We see that the change of momentum does not depend on the mass of the cars, as the force and time are the same all vehicles have the same change of momentum

8 0
3 years ago
About how much of Earth's water is available for humans to use?
lesya692 [45]

Answer:

0.3 %

Explanation:

Earth cleans and replenishes the water supply through the hydrologic cycle. The earth has an abundance of water, but unfortunately, only a small percentage, is even usable by people.

5 0
3 years ago
Two particles, one with charge -6.29 × 10^-6 C and one with charge 5.23 × 10^-6 C, are 0.0359 meters apart. What is the magnitud
navik [9.2K]

Answer:

Force, F = −229.72 N

Explanation:

Given that,

First charge particle, q_1=-6.29\times 10^{-6}\ C

Second charged particle, q_2=5.23\times 10^{-6}\ C

Distance between charges, d = 0.0359 m

The electric force between the two charged particles is given by :

F=k\dfrac{q_1q_2}{d^2}

F=9\times 10^9\times \dfrac{-6.29\times 10^{-6}\times 5.23\times 10^{-6}}{(0.0359)^2}

F = −229.72 N

So, the magnitude of force that one particle exerts on the other is 229.72 N. Hence, this is the required solution.

4 0
3 years ago
A scientist fixes a test charge q′ to point P and then measures the electrostatic force it experiences there. She then calculate
nordsb [41]

Answer:

<em>Correct answer: B.</em>

Explanation:

Electrostatic Field

It measures the electric effect of a charge distribution in its surroundings. If we wanted to test or measure the electric field by using a point-charge of value q', then the electric field is

\displaystyle E=\frac{F}{q'}

The electrostatic force between two point charges is

\displaystyle F=\frac{k\ q_1\ q'}{r^2}

So, the electric field is

\displaystyle E=\frac{\frac{k\ q_1\ q'}{r^2}}{q'}

\displaystyle E=\frac{k\ q_1}{r^2}

The theory shows that the electric field doesn't depend on the test charge used, i.e., if we now use q'=-q', the electric force will be of the same magnitude but in the opposite direction, thus the electric field will be the same. Let's recall the formula is used to compute the scalar value of the field, the direction must be studied separately.

Now, if we changed the test charge to another value, say 2q, the measured force will be

\displaystyle F=\frac{k\ q_1\ 2q}{r^2}

And the new electric field is

\displaystyle E=\frac{k\ q_1}{r^2}

We can see the electric field is not affected by the value of the test charge.

Finally, if we move the test charge to another location and keep the same charge, the electric force will vary and the electric field will be different.

Correct answer: B.

7 0
3 years ago
What conversion factor is needed to change from kilometers to meters?
ELEN [110]

The conversion factor needed to change from kilometers to meters is

D) 1000

Explanation:

The meter (m) is the SI units to measure distance.

The kilometer (km) is a sub-unit, where the prefix 'kilo' stands for 10^3, or 1000. This means that:

1 km = 1000 m

Therefore, if we have a length expressed in kilometers, we just need to multiply by 1000 to get the corresponding length in meters.

For instance, if we have a length of

L = 3.47 km

To convert in meters, we do:

L = 3.47 km \cdot (1000 \frac{m}{km})=3470 m

Learn more about distance here:

brainly.com/question/3969582

#LearnwithBrainly

5 0
3 years ago
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