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sweet-ann [11.9K]
3 years ago
5

The function of the ossicles in the middle ear is to transmit the vibrations of the tympanic membrane caused by sound waves prop

agated in air to the fluid-filled cochlea. In doing so, the ossicles change the nature of the vibrations. The ear tries to conserve the energy in the wave I,
where v is the wave speed, cramster-equation-2010731130406341613664 is the density of the medium, cramster-equation-2010731131286341613668 is the frequency of the wave and A is the amplitude of the wave.
Calculate the magnitude of the change in A that occurs. The density of air and water is 1.3x10–3g/cm3 and 1.0g/cm3, respectively, and the velocity of sound is 331 m/s in air and 1410 m/s in water. The frequency of the wave remains constant as the wave propagates. (Hint: Begin with to find .)
Physics
1 answer:
Daniel [21]3 years ago
6 0
A I hope I helpedddd
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Tara's cell phone plan costs $39.00 a month, which includes 100 text messages. After she uses all of her text messages, it will
vekshin1
I think it is $585.hope it is right
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How many legs does an arachnid have??
Virty [35]
An arachnid has eight legs.
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A 56-kg skater initially at rest throws a 5.0-kg medicine ball horizontally to the left. Suppose the ball is accelerated through
aniked [119]

Answer:

a_2=24.5\ \text{m/s}^2 towards right

a_1=2.1875\ \text{m/s}^2 towards left

Explanation:

m_1 = Mass of skater = 56 kg

m_2 = Mass of ball = 5 kg

v = Final velocity of ball = 7 m/s

u = Initial velocity of ball = 0

s = Distance the ball moved in the hand of the skater = 1 m

Moving left is considered and moving right is considered positive.

From kinematic equations of motion we have

v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{7^2-0^2}{2\times 1}\\\Rightarrow a=24.5\ \text{m/s}^2

So, the ball will move towards right with a magnitude of acceleration a_2=24.5\ \text{m/s}^2.

The force on the ball will be

F_2=m_2a_2\\\Rightarrow F_2=5\times 24.5\\\Rightarrow F_2=122.5\ \text{N}

The force on the ball is 122.5\ \text{N}

The reaction force on the skater will be equal to the force on the ball but will have opposite direction.

-F_1=F_2\\\Rightarrow -m_1a_1=F_2\\\Rightarrow a_1=-\dfrac{122.5}{56}\\\Rightarrow a_1=-2.1875\ \text{m/s}^2

So, the skater will move towards left with a magnitude of acceleration 2.1875\ \text{m/s}^2

4 0
3 years ago
A 65.0 kg diver is 4.90 m above the water, falling at speed of 6.40 m/s. Calculate her kinetic energy as she hits the water. (Ne
mojhsa [17]

Answer:

4452.5 J.

Explanation:

The diver have both kinetic and potential energy.

Ek = 1/2mv² ................. Equation 1

Where Ek = Kinetic Energy of the diver, m = mass of the diver, v = velocity of the diver.

Given: m = 65 kg, v = 6.4 m/s.

Substitute into equation 1

Ek = 1/2(65)(6.4²)

Ek = 1331.2 J.

Also,

Ep = mgh ............................ Equation 2

Where Ep =  Potential energy of the diver when its above the water, h = height of the diver above the water, g = acceleration due to gravity.

Given: m = 65 kg, h = 4.9 m, g = 9.8 m/s²

Substitute into equation 2.

Ep = 65(4.9)(9.8)

Ep = 3121.3 J.

Note: When she hits the water, the potential energy is converted to kinetic energy.

E = Ek+Ep

Where E = Kinetic energy of the diver when she hits the water.

E = 1331.2+3121.3

E = 4452.5 J.

3 0
3 years ago
How can you make gravity smaller and bigger
kobusy [5.1K]
The force of gravity = GMm / r^2, where G is gravitational constant, M is mass of one object, m is mass of another object, r is distance between them.

To make gravity smaller, decrease mass or increase distance.
To make gravity bigger, increase mass or decrease distance.
3 0
4 years ago
Read 2 more answers
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