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SpyIntel [72]
3 years ago
13

Harry liked to collect old movies. On 4 different days, he bought 2 movies. On 2 other days, he bought 3 movies each day. After

that he sold 2 sets of 2 movies. He figured out how many he had total, and then he divided that total into 2 groups to put onto his shelves. How many did he put on each shelf? Choose the expression that best matches this situation.
Mathematics
1 answer:
neonofarm [45]3 years ago
8 0

Answer:

Harry put 5 movies on each shelf.

Step-by-step explanation:

The information provided is:

  • On 4 different days, he bought 2 movies.
  • On 2 other days, he bought 3 movies each day.
  • After that he sold 2 sets of 2 movies.
  • He divided the remaining into 2 groups to put onto his shelves.

So, first Harry bought 2 movies on four different days.

That is, a total of 8 movies.

Then, he bought 3 movies on two other days.

That is, a total of 6 movies.

So, in total Harry bought 14 movies.

Now, he sold 2 sets of 2 movies.

That is, he sold 4 movies.

He has 14 - 4 = 10 remaining movies with him.

It is provided that he divided remaining movies into 2 groups to put onto his shelves.

So, he put 10/2 = 5 movies on each shelf.

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pantera1 [17]

Answer:

(4x + 1)(2x² - 5)

Step-by-step explanation:

Given

8x³ + 2x² - 20x - 5 ( factor the first/second and third/fourth terms )

= 2x²(4x + 1) - 5(4x + 1) ← factor out (4x + 1) from each term

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3 years ago
A Government company claims that an average light bulb lasts 270 days. A researcher randomly selects 18 bulbs for testing. The s
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Answer:

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question, we have that:

\mu = 270, \sigma = 90, n = 18, s = \frac{90}{\sqrt{18}} = 21.2

What is the probability that 18 randomly selected bulbs would have an average life of no more than 260 days?

This is the pvalue of Z when X = 260. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{260 - 270}{21.2}

Z = -0.47

Z = -0.47 has a pvalue of 0.3192.

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

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