Y > |x| + 5
<span>(0,5) when x = 0, y > 5 ...FALSE
</span>(1,7) when x = 1, y > 6 ...7>6...TRUE
(7,1) when x = 7, y > 12 ...FALSE
answer
<span>B.(1,7)</span>
Answer:
Quadrant 2
Step-by-step explanation:
:)
Step-by-step explanation:
We apply the pythagorean theorem on ABC.
AC^2=11^2+60^2 = 3600 + 121 = 3721
AC=61
Which means that sin(BAC) = 60/61.
However, sin^2(BAC) + cos^2(BAC)=1.
3600/3721 + cos^2(BAC) = 3721/3721.
cos^2(BAC) = 121/3721.
BAC is an acute angle so the cos is a positve number.
cos(BAC) = 11/61.
Lastly, x/60 = cos(BAC), so x= 660/61
