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Alex777 [14]
3 years ago
15

Ending time: 10:08 am elapsed time: 30 minutes

Mathematics
2 answers:
vredina [299]3 years ago
6 0
I  got this by taking 10:08:0:30  the answer is 10:38
Vlada [557]3 years ago
5 0
Subtract 30 minutes from 10:08.

First, subtract 8:

10:00

30 - 8 = 22

Now subtract 60 - 22:

60 - 22 = 38

So the time now is 9:38
You might be interested in
In ΔBCD, the measure of ∠D=90°, the measure of ∠C=77°, and CD = 41 feet. Find the length of BC to the nearest foot.
OLga [1]

Answer:

182 ft

Step-by-step explanation:

When you are not given a diagram, always draw one for yourself (see diagram).

When you have a right triangle (triangle with 90° angle), you can use the trigonometry ratios, You can remember them using SohCahToa. It is read like this:

<u>s</u>inθ = <u>o</u>pposite/<u>h</u>ypotenuse           Soh

<u>c</u>osθ = <u>a</u>djacent/<u>h</u>ypotenuse          Cah

<u>t</u>anθ = <u>o</u>pposite/<u>a</u>djacent                Toa

"θ" means the angle of reference (the angle you are talking about).

We are looking for the length of BC, which is the <u>hypotenuse</u>. I labelled it "d" (lowercase D) because it is opposite to ∠D.

We know ∠C = 77°. This will be our angle of reference (replace θ).

The side we know is DC, also known as "b" (lowercase B) because it's opposite to ∠B. "b" is the <u>adjacent</u> side when θ = C because "b" is touching ∠C.

Take the general trig. formula that has <u>hypotenuse</u> and <u>adjacent</u>: (cosine ratio)

cosθ = adjacent/hypotenuse

Substitute the variables specific for this problem.

cosC = b/d

Substitute the values you know.

cos77° = (41 ft) / d

Isolate "d" to the left side

dcos77° = d*\frac{41ft}{d}     Multiply both sides by "d"

dcos77° = 41 ft                          

dcos77° / cos77° = 41 ft / cos77°        Divide both sides by cos77°

d = 41 ft / cos77°                      Input into calculator

d = 182.261874....... ft           Unrounded answer

d ≈ 182 ft                       Rounded to nearest foot (whole number)

Remember d = BC. It's often easier to use one letter for calculations.

Therefore the length of BC is about 182 feet.

8 0
3 years ago
Heat travels from cold to hot. O True O False<br>​
Lady bird [3.3K]

Answer:

False

Take water heating up for example. Heat travels just from...heat!

7 0
3 years ago
How do you solve u/5+u/10-u/6=1
Zinaida [17]
Find the least common denominator for each of these fractions then complete the equation until it equals 1.

Common factor is 30
u/5 = 6u/30
u/10 = 3u/30
-u/6 = -5u/30

6u/30 + 3u/30 - 5u/30 = 1
4u/30 = 1
4u = 30
u = 7.5
8 0
3 years ago
Can I get help......​
Ivenika [448]
The answer is C -208 degrees Fahrenheit!
6 0
3 years ago
A university interested in tracking its honors program believes that the proportion of graduates with a GPA of 3.00 or below is
insens350 [35]

Answer:

The value of the test statistic and its associated p-value at the 5% significance level are -1.54 and 0.9382, respectively.

Step-by-step explanation:

A university interested in tracking its honors program believes that the proportion of graduates with a GPA of 3.00 or below is less than 0.16.

This means that the null hypothesis is:

H_{0}: p \geq 0.16

Testing this hypothesis, means that the alternate hypothesis is:

H_{a}: p > 0.16

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.16 is tested at the null hypothesis:

This means that \mu = 0.16, \sigma = \sqrt{0.16*0.84}

In a sample of 200 graduates, 24 students have a GPA of 3.00 or below.

This means that n = 200, X = \frac{24}{200} = 0.12

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.12 - 0.16}{\frac{\sqrt{0.16*0.84}}{\sqrt{200}}}

z = -1.54

Pvalue:

The pvalue is the probability of finding a sample mean above 0.12, which is 1 subtracted by the pvalue of z = -1.54.

Looking at the z-table, z = -1.54 has a pvalue of 0.0618

1 - 0.0618 = 0.9382

The value of the test statistic and its associated p-value at the 5% significance level are -1.54 and 0.9382, respectively.

6 0
3 years ago
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