Buffers such as bicarbonate buffer, citrate buffer and phosphate buffer are important in living system. pH of blood is near to neutrality (7.4). If the pH of blood increases, these buffers help in maintaining the blood pH. Increase in blood pH leads to certain diseases such as alkalosis. This further leads to muscle spasm and respiratory diseases.
Bicarbonate buffer helps to maintain the blood pH if it falls towards acidic range or increases towards alkalinity. It helps in decreasing acidity and increasing alkalinity by forming carbon dioxide gas. Increase in blood pH towards alkalinity is also maintained by excreting the bicarbonates into the urine. Similar action is also seen in case of phosphate buffer and citrate buffer.
Answer: If these buffers are not present in a living system then the change of pH cannot be altered or put back to normal. These buffers help to maintain the pH of the living system so that cells can work properly.
Low concentration to high concentration and requires energy
Answer: B. A property owner clear-cutting all of the trees on his land to sell for timber.
Explanation:
The tragedy of the commons is a problem whereby an individual pursue his or her own personal gain at the expense of the overall well-being of everyone in the society.
In this question, the tragedy of commons will be a property owner clear-cutting all of the trees on his land to sell for timber. Even though the owner makes some income for himself, this act will bring about soil erosion, depletion of resource or flood. He neglected the society in order to satisfy his own needs.
Answer:
Because we can see it happen in the animal kingdom
Explanation:
Answer: The estimated size of the population is 150
Explanation: For the Mark-Recapture method, there is a formula that can be used:
N = (M × C)/R
where :
N = estimated number of individuals in the population
M = number of individuals captured and arked
C = total number captured the second time (with and without a mark)
R= number of individuals ecaptured (those with a mark)
So with this formula we can calculate an estimation of the population of rodents. Because there is no number of rodents captured the second time given, we will assume 30 was caught again, making the 20% found marked being 6. We calculate it as:
N = (M × C)/R
:N = ( 30 × 30)/ 6
:N = 900/6
:N = 150 estimated rodents in the population