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igomit [66]
2 years ago
6

What is the constant of proportionality in this proportional relationship?

Mathematics
1 answer:
ArbitrLikvidat [17]2 years ago
5 0

Answer:

Sorry, I'm late but it's \frac{5}{12} Hope this helps :D

Step-by-step explanation:

I took the test

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Is 3/5 equivalent to 0.35
marin [14]
3/5 is equivalent to 0.6
This is because if you times 2 to the numerator and denominator(top and bottom of the fraction) you will get 6/10 which is 0.6
8 0
2 years ago
I need help on this question
katen-ka-za [31]
Measure of the interior angle: 180 -113: 67
the measure of interior angle is 67.
8 0
3 years ago
When Belinda asked him to what pages his book was opened, he replied that the product of the facing pages was 87,912. To what pa
Liono4ka [1.6K]

Answer:

His book was opened at Page no.296 and Page no.297

Step-by-step explanation:

Let the page number of one page be x

Page number of page facing page no. x = x+1

We are given that the product of the facing pages was 87,912.

So, x(x+1)=87912

x^2+x=87912

x^2+x-87912=0

x^2-296x+297x-87912=0

x(x-296)+297(x-296)=0

(x+297)(x-296)=0

x=296,-297

Since Page no. cannot be negative

So, x=296

x+1=296+1=297

So, his book was opened at Page no.296 and Page no.297

5 0
2 years ago
One employee pours 6 ounces of coffee in the large frappuccino.
Reil [10]

Answer:

The employee's action <u>is not following the instructions</u>.

Step-by-step explanation:

The drinks table has some recommendations to make some drinks exclusive to the establishment such as the Large Frapuccino or the Small Chai Tea, which in its first line corresponding to the Large Frapuccino specifies that at least 8 ounces of coffee should be used, which it wants to say is the <u>minimum amount of coffee that can be added to it is 8 ounces</u>, and the value could be higher than that, but never lower, which is why by adding only 6 ounces to the Frapuccino you are totally ignoring the instructions.

8 0
2 years ago
Fill in the blanks below to make a true statement. In a binomial experiment with n trials and probability of success p, if np (1
Sergeu [11.5K]

Answer:

\mu_{x}=np

\sigma^2_{X}=np(1-p)

Step-by-step explanation:

∵ When x is a random variable having distribution B(n, p), then for sufficiently large value of n, the following random variable has a standard normal distribution,

\frac{x-\mu}{\sigma}\sim N(0,1)

Where,

\mu=np

\sigma^2=np(1-p)

Here the variable X has a binomial distribution,

Such that, np (1 - p) ≥ 10 ⇒ n is sufficiently large.

Where, n is the total numbers of trials, p is success in each trials,

So, the mean of variable X is,

\mu_{X} = np

And, variance of variable X is,

\sigma^2{X}=np(1-p)

3 0
3 years ago
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