Answer:
A
Step-by-step explanation:
look where the plot is Set 1 is at 8 and Set 2 is at 10. obviously 10 is greater than 8
Answer:
x = (5 + i sqrt(15))/4 or x = (5 - i sqrt(15))/4
Step-by-step explanation:
Solve for x:
2 x^2 - 5 x + 5 = 0
Hint: | Using the quadratic formula, solve for x.
x = (5 ± sqrt((-5)^2 - 4×2×5))/(2×2) = (5 ± sqrt(25 - 40))/4 = (5 ± sqrt(-15))/4:
x = (5 + sqrt(-15))/4 or x = (5 - sqrt(-15))/4
Hint: | Express sqrt(-15) in terms of i.
sqrt(-15) = sqrt(-1) sqrt(15) = i sqrt(15):
Answer: x = (5 + i sqrt(15))/4 or x = (5 - i sqrt(15))/4
Answer:
Addition Property
Step-by-step explanation:
Added 4 on both sides to equate the solution
Consider ∆JWZ and ∆JKZ
WZ~KJ (given)
<u>/</u><u> </u><u>WZJ</u>~<u>/</u><u> </u>KJZ (given)
JZ~JZ (common)
Therefore,
∆JWZ~∆JKZ by SAS congruence rule.
JW~ZK by CPCT.
Answer:
first choice is the correct answer
