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MatroZZZ [7]
4 years ago
12

Find the perimeter of the triangle defined by the coordinates (9, 0), (-5, 0), and (-10, 6). (Round to nearest tenth)

Mathematics
1 answer:
eduard4 years ago
7 0
The perimeter is 41.7.

We first find the distance between each vertex using the distance formula:
d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}
\\
\\=\sqrt{(0-0)^2+(-5-9)^2}=\sqrt{0^2+(-14)^2}=\sqrt{196}=14
\\
\\d=\sqrt{(6-0)^2+(-10--5)^2}=\sqrt{6^2+(-5)^2}=\sqrt{36+25}=\sqrt{61}
\\=7.81
\\
\\d=\sqrt{(6-0)^2+(-10-9)^2}=\sqrt{6^2+(-19)^2}=\sqrt{36+361}=\sqrt{397}
\\=19.92

We now find the perimeter by adding all of the side lengths:
14+7.81+19.92 = 41.73 ≈ 41.7
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