Answer:
(a) ΔP=0.0245 kPa
(b) P=9.14 kPa
(c)ΔP=0.0245 kPa
Explanation:
(a) As it is perfect gas we can use
(P₁V₁)/T₁=(P₂V₂)/T₂
Since this constant volume so
P₁/T₁=P₂/T₂
T₂ is change in temperature
T₂=1.00+273.16
T₂=274.16 K

ΔP=6.71449-6.69
ΔP=0.0245 kPa
(b) As

(c) Same steps as in part (a)

ΔP=9.164-9.14
ΔP=0.0245kPa
Could you scroll up a little so I can see the first part of the question- I MIGHT be able to help you then. Thanks!
Answer:
do explain what u need help with?
Answer:
cal
Explanation:
= mass of ice = 100 g = 0.1 kg
= specific heat of ice = 0.5 cal/(kg°C)
= specific heat of water = 1 cal/(kg°C)
= Latent heat of fusion of ice = 80 J/g
= initial temperature of ice = - 20 °C
= final temperature of ice = 50 °C
Q = Heat gained
Heat gained is given as


cal