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tensa zangetsu [6.8K]
3 years ago
9

How do I solve acceleration word problems?

Physics
1 answer:
umka2103 [35]3 years ago
8 0
Acceleration just means that you add the amount of acceleration to the object's current velocity.

So if something is moving at 5m/s^2, at one second it would be moving 5m/s, then at two it would be 25m/s, then at three 125m/s, etc.

I haven't been in physics for almost a year, so I may be incorrect. But that's what I remember.
You might be interested in
A constant-volume perfect gas thermometer indicates a pressure of 6.69 kPa at the triple point temperature of water (273.16 K).
mina [271]

Answer:

(a) ΔP=0.0245 kPa

(b) P=9.14 kPa

(c)ΔP=0.0245 kPa

Explanation:

(a) As it is perfect gas we can use

(P₁V₁)/T₁=(P₂V₂)/T₂

Since this constant volume so

P₁/T₁=P₂/T₂

T₂ is change in temperature

T₂=1.00+273.16

T₂=274.16 K

P_{2}=(\frac{6.69}{273.16} )*274.16\\P_{2}=6.71449 kPa

ΔP=6.71449-6.69

ΔP=0.0245 kPa

(b) As

P_{2}=(\frac{6.69}{273.16} )*373.16\\P_{2}=9.14 kPa

(c) Same steps as in part (a)

P_{2}=(\frac{9.14}{373.16} )*374.16\\P_{2}=9.164kPa

ΔP=9.164-9.14

ΔP=0.0245kPa

8 0
3 years ago
Measuring the size of a specific object might include which of these SI units?
defon

D. Meter, Kilogram

Explanation:

  • There are certain units for the measurements things which are around us.
  • This is the SI units for the measurement of the size of the objects.
  • SI units are international unit systems, they are one who accepted around the world.
  • It is called the International System of Units, used to expresses the phenomenon happens around us in a scientific method
  • Here, the meter is the unit for Length in the International System of Units and Kilogram is to represent the mass of the object in SI units system.
3 0
4 years ago
Can someone help me with these two please.
Alex17521 [72]
Could you scroll up a little so I can see the first part of the question- I MIGHT be able to help you then. Thanks!
3 0
3 years ago
Read 2 more answers
Help thank you...............
Sergeu [11.5K]

Answer:

do explain what u need help with?

3 0
3 years ago
Calculate the heat gained by 100 grams of ice at -20°C in order to become water at 50°C. ( C = .5 for ice and C = 1 for water, Q
Korvikt [17]

Answer:

6008 cal

Explanation:

m_{i} = mass of ice = 100 g = 0.1 kg

c_{i}  = specific heat of ice = 0.5 cal/(kg°C)

c_{w}  = specific heat of water = 1 cal/(kg°C)

L  = Latent heat of fusion of ice = 80 J/g

T_{i}  = initial temperature of ice = - 20 °C

T_{f}  = final temperature of ice = 50 °C

Q = Heat gained

Heat gained is given as

Q = m_{i} c_{i}(0 - (T_{i}))+ m_{i}L + m_{i}c_{w}(T_{i} - 0)

Q = (100) (0.5) (0 - (- 20))+ (0.1)(80) + (100) (1)(50 - 0)

Q = 6008 cal

8 0
3 years ago
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