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Vladimir [108]
4 years ago
9

What do hurricanes use to gain strength?

Physics
2 answers:
Svetradugi [14.3K]4 years ago
7 0

Answer:

The warmth of the ocean water

Explanation:

MAXImum [283]4 years ago
5 0
Just the right types of conditions with warm water and weak wind shear allow them to strengthen.
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Was the first chemist to organize elements by atomic number
Arturiano [62]

Answer:

Dimitri Mendeleev

Explanation:

This man started the development of the periodic table, by arranging elements by atomic mass.  

5 0
3 years ago
Read 2 more answers
Can someone help me
Nady [450]
The answer is D 10x21
7 0
3 years ago
If Earth's mass was cut in half, what would happen to your mass? Group of answer choices
Alex777 [14]

Answer:

nothing, mass is not affected by gravitational force

Explanation:

Weight is the gravitational force a planet exerts on a mass on the surface.

It is the product of the mass of an object with the gravitational acceleration that the planet produces.

The weight is the gravitational force

W=mg

where,

m = Mass of the object

g = Acceleration due to gravity = 9.81 m/s²

Mass is the property that matter has which opposes the force being applied to it. It is intrinsic to the object itself and does not change according to the gravitational force. But, the weight changes.

5 0
4 years ago
Consider the power dissipated by the two circuits in the video. The ratio of power dissipation in the parallel circuit to that i
klemol [59]

Answer:

A)

Explanation:

  • In a series circuit,  if we assume that each bulb has a resistance R, the equivalent resistance, is the sum of all the resistances, in this case, 3*R.
  • The power dissipated in this resistance, can be expressed as follows:

       P_{series}  = V*I = V*(\frac{V}{R_{eq}})  = \frac{V^{2}}{3*R} (1)

  • In the parallel circuit, the equivalent resistance, is equal to 1/3*R.
  • The power dissipated in this resistance, can be expressed as follows:

       P_{//}  = V*I = V*(\frac{V}{R_{eq}})  = \frac{V^{2}}{\frac{R}{3} } (2)

  • In order to take the ratio of both powers, we can divide both sides of (1) and (2) , as follows:

        \frac{P_{//} }{P_{series} } =\frac{V^{2}}{\frac{R}{3}} * \frac{3*R}{V^{2}} = 9

  • The ratio of power dissipation in the parallel circuit to that in the series circuit is 9 times.
5 0
4 years ago
4 kg of water was
morpeh [17]

Given :

Mass =5kg

T

1

=20

∘

C,T

2

=100

∘

C

ΔT=100−20=80

∘

C

Q=m×C×ΔT

where C= specific heat capacity of water

=4200J/(kgK)

Q=5×4200×80

=1680000 Joule.

=1680KJ

6 0
3 years ago
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