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katen-ka-za [31]
3 years ago
10

A plane is landing. It started at 400m/s and ended up at 50m/s after 30 seconds. What is it's acceleration?

Physics
1 answer:
quester [9]3 years ago
4 0

Give u = start velocity

        v = end velocity

v = u + at

50 = 400 + a*30

30a = -350

a = -116.67 m/s^{2}

**Why the accecleration is negative number**

Because displacement, velocity, and acceleration are VECTOR QUANTITIES.

Vector Quantity must have direction.

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Air at 27oC and 1 atm flows over a flat plate 40 cm in length and 1 cm in width at a speed of 2 m/s. The plate is heated over it
irga5000 [103]

Answer:

Heat transferred = 22.9 watt

Explanation:

Given that:

T_1 = 27°C = (273 + 27) K = 300 K

T_2= 600°C = (600 +273) K = 873 K

speed v = 2 m/s

length x = 40 cm = 0.4 cm

width = 1 cm = 0.001 m

The heat transferred from the plate can be calculate by using the formula:

Heat transferred = h×A ×ΔT

From the tables of properties of air, the following values where obtained.

k = 0.02476 \ W/m.k  \\ \\  \rho = 1.225 \ kg/m^3 \\ \\ \mu = 18.6 \times 10^{-6} \ Pa.s \\ \\ c_p = 1.005 \ kJ/kg

To start with the reynolds number; the formula for calculating the reynolds number can be expressed as:

reynolds number = \dfrac{\rho \times v \times x }{\mu}

reynolds number = \dfrac{1.225 \times 2 \times 0.4}{18.6 \times 10^{-6}}

reynolds number = \dfrac{0.98}{18.6 \times 10^{-6}}

reynolds number = 52688.11204

Prandtl number = \dfrac{c_p \mu}{k}

Prandtl number = \dfrac{1.005 \times 18.6 \times 10^{-6} \times 10^3}{0.02476}

Prandtl number = \dfrac{0.018693}{0.02476}

Prandtl number = 0.754963

The nusselt number for this turbulent flow over the flat plate  can be computed as follows:

Nusselt no = \dfrac{hx}{k} = 0.0296 (Re) ^{0.8} \times (Pr)^{1/3}

\dfrac{h \times 0.4}{0.02476} = 0.0296 (52688.11204) ^{0.8} \times (0.754968)^{1/3}

\dfrac{h \times 0.4}{0.02476} =161.4252008}

h  =\dfrac{161.4252008 \times 0.02476}{ 0.4}

h = 9.992 W/m.k

Recall that:

The heat transferred from the plate can be calculate by using the formula:

Heat transferred = h×A ×ΔT

Heat transferred = h\times A \times (T_2-T_1)

Heat transferred = 9.992 × (0.4 × 0.01) ×(873-300)

Heat transferred = 22.9 watt

6 0
3 years ago
The dwarf planet Ceres contains over 50% of the mass of the main asteroid belt.
PolarNik [594]

False

Explanation:

Called an asteroid for many years, Ceres is so much bigger and so different from its rocky neighbors that scientists classified it as a dwarf planet in 2006. Even though Ceres comprises 25 percent of the asteroid belt's total mass, tiny Pluto is still 14 times more massive.

6 0
2 years ago
What Coulombs discovered almost 300<br> years ago
tamaranim1 [39]

Answer:

ummm hehe this is my time to shine

Explanation:

  MERICIA!!!!!!!!!!!!!!!!!!!!!!!

5 0
3 years ago
Read 2 more answers
At each of the designated points, rotate the given vector to indicate the direction of the force exerted by the water on either
GrogVix [38]

Answer:

The direction of the force at A and B is perpendicular to the walls of the container.

The direction of the force at C is down.

The direction of the force in D is up

The direction of the force at E is to the left.

The attached figure shows the forces exerted by the water at points A, B, C, D and E.

Explanation:

The water is in contact with the bowl and with the fish. It exercises at points A, B, C, D and E, but the direction is different from the force.

The fish has a buoyant force on the water and that direction is up. The direction of at point D is up.

The column of water on the fish has a downward force, therefore the direction of the force at point C is down. The water column to the right of the fish has a force to the left, and the direction at point E is to the left.

The water will exert a force on the walls of the container and this force at points A and B is a on the walls of the container.

4 0
3 years ago
An office window has dimensions 3.1 m by 2.1 m. As a result of the passage of a storm, the outside air pressure drops to 0.954 a
Virty [35]

Answer:

Net forces which pushes the window is 30342.78 N.

Explanation:

Given:

Dimension of the office window.

Length of the window = 3.1 m

Width of the window = 2.1 m

Area of the window = (3.1\times 2.1) = 6.51\ m^2

Difference in air pressure = Inside pressure - Outside pressure

                                           = (1.0-0.954) atm = 0.046 atm

Conversion of the pressure in its SI unit.

⇒  1 atm = 101325 Pa

⇒ 0.046 atm = 0.046\times 101325 =4660.95 Pa

We have to find the net force.

We know,

⇒ Pressure = Force/Area

⇒ Pressure=\frac{Force }{Area}

⇒ Force =Pressure\times Area

⇒ Plugging the values.

⇒ Force =4660.95\times 6.51

⇒ Force=30342.78 Newton (N)

So,

The net forces which pushes the window is 30342.78 N.

3 0
3 years ago
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