Which subatomic particle has the least mass?

Would a pair of scissors with really long blades and a short handle be practical? Why or why not?

Lana71 [14]

Yes, for balance.hope this helped.

6 0

3 years ago

Which system of measurement has been standardized worldwide for scientific uses?

belka [17]

<h2>Answer: The Systeme international (International System of Units)</h2>

The International System of Units (SI) is used in almost every country in the world (<em>except Burma, Liberia and the United States</em>).

This system was created in 1960 by the 11th General Conference of Weights and Measures in France and is made up of seven basic units:

-Ampere (electric current)

-Kelvin (temperature)

-Second (time)

-Meter (length)

-Kilogram (mass)

-Candela (luminous intensity)

-Mol (amount of substance) *added to the system in 1971

Plus an unlimited number of derived units from the main ones.

7 0

3 years ago

Determine the potential energy of a 625-kg roller coaster car that is at the top of a hill that is 135 m tall.

Mice21 [21]

Answer:

Caused by gravity and the roller coaster's position, the potential energy is stored in the roller coaster. For example, this ball is at the top of a hill, where potential energy is at it's highest.

Explanation:

4 0

3 years ago

Two rings of radius 5 cm are 20 cm apart and concentric with a common horizontal x-axis. The ring on the left carries a uniforml

Yanka [14]

Answer:

The electric field due to the right ring at a location midway between the two rings is $2.41\times10^{3}\ V/m$

Explanation:

Given that,

Radius of first ring = 5 cm

Radius of second ring = 20 cm

Charge on the left of the ring = +30 nC

Charge on the right of the ring = -30 nC

We need to calculate the electric field due to the right ring at a location midway between the two rings

Using formula of electric field

$E=\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{qx}{(x^2+R^2)^{\frac{3}{2}}}$

Put the value into the formula

$E=\dfrac{9\times10^{9}\times30\times10^{-9}\times0.1}{((0.1)^2+(0.2)^2)^{\frac{3}{2}}}$

$E=2.41\times10^{3}\ V/m$

Hence, The electric field due to the right ring at a location midway between the two rings is $2.41\times10^{3}\ V/m$

3 0

4 years ago

An applied pulling force of 100 N is used to accelerate an object to the right along a rough surface that offers 40 N of frictio

blondinia [14]

Answer:

$9.8 m/s^2$

Explanation:

First of all, we analyze the vertical direction.

Along this direction, the object is in equilibrium, so its acceleration is zero, and therefore the net force on it is zero. There are only two forces acting on the object vertically: the weight, W (downward), and the normal force, N (upward), and since the net force must be zero, we can write

$W=N$