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inysia [295]
3 years ago
8

Which element is a metalloid? Check all that apply. selenium (Se) polonium (Po) silicon (Si) iodine (I) tin (Sn) antimony (Sb) p

hosphorus (P)

Chemistry
2 answers:
bulgar [2K]3 years ago
8 0
The metalloids are highlighted in the table.

Of the elements in the question, the following are metalloids...

<span>antimony (Sb)
</span><span>silicon (Si)
</span><span>polonium (Po) 

</span>

SVETLANKA909090 [29]3 years ago
8 0

Answer: Polonium (Po), Silicon (Si), Antimony(Sb)

Explanation: Metalloids are the elements which exhibits some properties of both metals and non-metals. They are generally called as  semi-metal. There are in total 7 metalloids in whole periodic table. They are:

Boron (B), Silicon (Si), Germanium (Ge), Arsenic (As), Antimony (Sb), Telurium (Te) and Polonium (Po).

From, the list and periodic table attached, it is visible that only Silicon, Polonium and antimony are the metalloids from the elements given.

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8 0
1 year ago
What is the temperature of water at low latitudes please help me
bixtya [17]
The average temperature of the ocean surface waters is about 17 degrees Celsius (62.6 degrees Fahrenheit).

Hoped that helped
6 0
3 years ago
At which volume of base added was all the acid neutralized?
Scilla [17]

Answer: The answer is A

im 86% sure

5 0
2 years ago
Choose the correct answer to complete the paragraph about the acceptance of the heliocentric model. In the second century BCE, t
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4 0
3 years ago
Read 2 more answers
In the laboratory a student uses a "coffee cup" calorimeter to determine the specific heat of a metal. She heats 19.6 grams of z
storchak [24]

Answer:

The specific heat of zinc is 0.375 J/g°C

Explanation:

<u>Step 1: </u>Data given

Mass of zinc = 19.6 grams

Mass of water = 82.9 grams

Initial temperature of zinc T1= 98.37 °C

Initial temperature of water T1= 24.16 °C

Final temperature of water (and zinc) T2 = 25.70 °C

Specific heat of water = 4.184 J/g°C

<u>Step 2: </u>Calculate Specific heat of zinc

Q=m*c*ΔT

Qzinc = -Qwater

m(zinc)*C(zinc)*ΔT(zinc) = -m(water)*C(water)*ΔT(water)

⇒ with mass of water = 82.9 grams

⇒ with C(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.70 - 24.16 = 1.54

⇒ with mass of zinc = 19.6 grams

⇒ with C(zinc) = TO BE DETERMINED

⇒ with ΔT(zinc) = T2 -T1 = 25.70 - 98.37 = -72.67°C

Qzinc = -Qwater

m(zinc)*c(zinc)* ΔT(zinc) = - m(water)*c(water)* ΔT(water)

19.6g* C(zinc) * (-72.67°C) = - 82.9g* 4.184 J/g°C * 1.54 °C

-1424.332*C(zinc) = -534.155

C(zinc) = 0.375 J/g°C

The specific heat of zinc is 0.375 J/g°C

4 0
3 years ago
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