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Lyrx [107]
2 years ago
10

At which volume of base added was all the acid neutralized?

Chemistry
1 answer:
Scilla [17]2 years ago
5 0

Answer: The answer is A

im 86% sure

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I don’t know what to say
Margaret [11]

Answer:

ugh it’s not coming out

Explanation:

5 0
2 years ago
Jim and Jan were racing in a 400 meter event. Jim ran the race in 44.32 seconds. Jan ran the race in 42.21 seconds. Calculate th
nordsb [41]

Answer:

2.11

Explanation:

44.32- 42.21=2.11

Hope this helps

4 0
2 years ago
Read 2 more answers
A certain shade of blue has a frequency of 7.26 × 1014 Hz. What is the energy of exactly one photon of this light?
Gekata [30.6K]
7.20 it the energy because


10\7.26 is 7.20
- 70
26
-20
6
6 0
3 years ago
Read 2 more answers
What makes calcium and nitrogen different list two differences
liberstina [14]

Answer:

the difference in electronegativity is so large (2.04) that the bonding electrons spend almost all their time on the nitrogen atom.

Explanation:

Because calcium loses 2 electrons to become Ca2+, and nitrogen gains 3 electrons to become N3−, you need two calcium atoms and three nitrogen atoms in order to form a neutral compound.

6 0
3 years ago
As a scuba diver descends under water, the pressure increases. At a total air pressure of 2.71 atm and a temperature of 25.0 C,
Semenov [28]

Answer:

1.32\times 10^{-3} mol/Lis the solubility of nitrogen gas in a diver's blood.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{N_2}=K_H\times p_{liquid}

where,

K_H = Henry's constant = 6.26 \times 10^{-4}mol/L.atm

p_{N_2} = partial pressure of nitrogen

p_{N_2}= P\times \chi_{N_2} (Raoult's law)

=2.71 atm\times 0.78=2.1138 atm

C_{N_2}=6.26 \times 10^{-4}mol/L.atm\times 2.1138 atm

C_{N_2}=1.32\times 10^{-3} mol/L

1.32\times 10^{-3} mol/Lis the solubility of nitrogen gas in a diver's blood.

3 0
3 years ago
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