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Lyrx [107]
3 years ago
10

At which volume of base added was all the acid neutralized?

Chemistry
1 answer:
Scilla [17]3 years ago
5 0

Answer: The answer is A

im 86% sure

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The final electron acceptor of the electron transport chain that functions in aerobic oxidative phosphorylation is The final ele
MissTica

Answer:

The final electron acceptor of the electron transport chain is oxygen

Explanation:

Four electrons gotten from cytochrome c are involved in the conversion of a molecule of oxygen (O2) to two molecules of water (H2O). This final electron transfer occurs in complex IV. Complex IV, also known as cytochrome c oxidase, facilitates the the use of four protons from the matrix of the mitochondrion, in the production of water molecules while pumping four protons to the intermembrane space of the mitochondrion.

8 0
3 years ago
Identify the for of energy<br><br> (A)thermal<br> (B)kinetic<br> (C)chemical<br> (D)electrical
RoseWind [281]

Answer:

<u>C Chemical Energy</u>

Explanation:

food gives us chemical energy which may be transformed to other later..

<em><u>please mark me brainliest</u></em>

3 0
3 years ago
Read 2 more answers
A trench is a. Cold and shallow
nexus9112 [7]

Answer:

D

Explanation:

i think

4 0
3 years ago
Read 2 more answers
If the density of mercury is 13.6 g/mL, what is the mass of 25.4 cm3 of<br> mercury?
Anettt [7]

Answer:

345.44 g or 0.34544 kg

Explanation:

Applying

D = m/V...................... Equation 1

Where D = Density of mercury, m = mass of mercury, V = Volume of mercury.

make m the subject of the equation

m = D×V................. Equation 2

From the question,

Given: D = 13.6 g/mL = 13.6 g/cm³, V = 25.4 cm³

Substitute these values into equation 2

m = 13.6×25.4

m = 345.44 g

m = 0.34544 kg

Hence the mass of mercury is 345.44 g or 0.34544 kg

4 0
3 years ago
when 5.60g of an iron oxide is heated with carbon, 3.92g of iron is produced. calculate the empirical formula of the iron oxide
svetlana [45]

Answer:  Fe2O3

Explanation:

  5.60 g Iron Oxide

-  3.92 g Iron

===========

=  1.68 g Oxygen

Convert Fe and O to moles:

3.92 g Iron/55.85 = 0.0702 moles Fe

1.68 g Oxygen/16 = 0.105 moles O

The ratio of O to Fe is 1.50.  There are 3/2 O for each Fe.  Multiply by 2 to get whole numbers:  2Fe for every 3O:  Fe2O3

5 0
2 years ago
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