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erastovalidia [21]
2 years ago
6

1.0250 - 0.00063 = O 1.02 1.0243 1.02437 DONE

Chemistry
2 answers:
larisa86 [58]2 years ago
8 0

The answer is B aka 1.0250 :)

miss Akunina [59]2 years ago
7 0

Answer:1.0243

Explanation: I think that is it

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C(s) + S8(s) → CS2(l)
Vanyuwa [196]
The balanced chemical reaction is written as:

<span>4C(s) + S8(s) → 4CS2(l)

We are given the amount of carbon and sulfur to be used in the reaction. We need to determine first the limiting reactant to be able to solve this correctly.

</span>7.70 g C ( 1 mol / 12.01 g) =0.64 mol C
19.7 g S8 ( 1 mol / 256.48 g) = 0.08 mol S8

The limiting reactant would be S8. We use this amount to calculate.

0.08 mol S8 ( 4 mol CS2 / 1 mol S8 ) ( 256.48 g / 1 mol ) = 78.8 g CS2
4 0
3 years ago
Have an infinite number of significant figures
vovikov84 [41]
The answer is: Non-zero
7 0
2 years ago
The decomposition of ammonia is: 2 NH3(g) ⇌ N2(g) + 3 H2(g). If Kp is 1.5 × 103 at 400°C, what is the partial pressure of ammoni
ValentinkaMS [17]

Answer:

"6.7\times 10^{-4} \ atm" is the right answer.

Explanation:

Given:

Partial pressure of N_2,

= 0.20 atm

Partial pressure of H_2,

= 0.15 atm

K_p = 1.5\times 10^3 at 400^{\circ} C

As we know,

⇒ K_p = \frac{pN_2\times pH_2^3}{pNH_3^2}

By putting the values, we get

    1.5\times 10^3=\frac{0.20\times (0.15)^3}{pNH_3^2}

        pNH_3^2 = \frac{0.000675}{1.5\times 10^3}

                    =6.7\times 10^{-4} \ atm

                   

3 0
2 years ago
What volume of 6.58M HCI is needed to make 500. mL of 3.00M HCI?
zmey [24]

Answer:

228 mL

Explanation:

M1*V1 = M2*V2

M1 = 6.58 M

V1 = ?

M2 = 3.00 M

V2 = 500 mL

V1 = M2*V2/M1 = 3.00M*500.mL/6.58 M = 228 mL

3 0
3 years ago
Difference between sodium ion and sodium atom.<br>(give in points not in paragraph)​
Natali5045456 [20]

Answer:

Explanation:

SODIUM ATOM;

SODIUM ATOM IS NEUTRAL

SODIUM ION;

IT IS A CHARGED SPECIE WITH A CHARGE OF +1

SODIUM ATOM:

THE NUMBER OF PROTONS AND ELECTRONS ARE SAME ie:11

SODIUM ION:

NUMBER OF PROTONS AND ELECTRONS ARE NOT SAME ie. ELETRON: 10, PROTONS:11

HOPE IT WILL HELP:)

3 0
2 years ago
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