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erastovalidia [21]
3 years ago
6

1.0250 - 0.00063 = O 1.02 1.0243 1.02437 DONE

Chemistry
2 answers:
larisa86 [58]3 years ago
8 0

The answer is B aka 1.0250 :)

miss Akunina [59]3 years ago
7 0

Answer:1.0243

Explanation: I think that is it

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4 0
3 years ago
You have 67.2 liters of oxygen at standard temperature and pressure. How many moles of oxygen molecules do you have? *
enot [183]

Answer:

Number of moles is 3.0moles

Explanation:

Volume (v) = 67.2L

Pressure at STP = 1atm

Temperature at STP = 273.15K

R = 0.082J/mol.K

Number of moles (n) = ?

From ideal gas equation,

PV = nRT

P = pressure

V = volume of the gas

n = number of moles

R = ideal gas constant

T = temperature of the gas

PV = nRT

solving for n,

n = PV / RT

n = (1.0 * 67.2) / (0.082 * 273.15)

n = 67.2 / 22.398

n = 3.0 moles

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3 0
3 years ago
7. A movable piston is allowed to cool from 392°F to 104°F. If the initial volume is 105 mL,
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Answer:

27.9 mL

Explanation:

To find the new volume, you need to use the Charles' Law equation:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature.

V₁ = 105 mL                     V₂ = ? mL

T₁ = 392 °F                       T₂ = 104 °F

V₁ / T₁ = V₂ / T₂                                            <----- Charles' Law

105 mL / 392 °F = V₂ / 104 °F                     <----- Insert values

0.26785 = V₂ / 104 °F                                 <----- Simplify left side

27.9 = V₂                                                     <----- Multiply both sides by 104

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5 0
3 years ago
4 pts
Digiron [165]

First we need to find the number of moles that 43.9g of gallium metal is. We can do this by finding the molar weight of gallium and cross-multiplying to cancel out units:

\frac{1mole}{69.723g} *\frac{43.9g}{1} =0.63MOLga

So we are dealing with 0.63 moles of gallium metal.

We can take from the balanced equation that 4 moles of gallium metal will react completely with 3 moles of oxygen gas. We can take this ratio and make a proportion to find the amount of oxygen gas, in moles, that will react completely with 0.63 moles of gallium metal:

\frac{4molesGa}{3moles02} =\frac{0.63molesga}{xmoleso2}

Cross multiply and solve for x:

4x=1.89

x=47 molesO₂

So now we know that 0.47 moles of oxygen gas will react with 43.9g of gallium metal.

7 0
3 years ago
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